RAV = ? L 2P L. L. P RBV = ? W = 4 lbs/ft L= 12 ft P = 5 lbs

As a follow question to the follow question. Could you explain in detailed how you came about the equation to solve for the reaction at A and B. In a beam like this or any other sort of beam how can I determine how many reactions I have. Also how did you know that the shear force is -250 and bending moment is -250x at section CA could you go more in depth on how you came to that conclusion.

Determine all the reactions of the given structure. The surface against which the support D is sitting is perpendicular to the element CD. Given: X = 10 kN. X.KN əITANDARTAIL FINAN |———— 4 6 kN/m 4 m 20 KN 4 m O 4 m The magnitude of the reaction at A is Ax= The magnitude of the reaction at A is Ay= The magnitude of the reaction at Dis D The magnitude of the reaction at D is Dy etməørstetten D T 3 m 3 m kN, and the reaction is (Click to select) ✓ kN, and the reaction is (Click to select) kN, and the reaction is (Click to select) kN, and the reaction is (Click to select)

Consider the frame shown in (Figure 1). Suppose that P = 400 N and M = 800 N? m. Find the reaction at C, so find Cx and Cy. Please help, show all the steps. Thanks! P M T 1m 1m B -1 m- -2 m- A C