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Transcribed Image Text:R3
Problem 5: An electric circuit consisting of wires, batteries, and
resistors is shown. All currents have been labeled and assigned
directions.
I
R2
R1
Part (a) Which statement is a correct expression of Kirchhoff's Junction Rule for currents with labels and directions
assigned on the above figure?
MultipleChoice :
1) I1 + I2 - 13 = 0
2) I1 + I2 + I3 = 0
3) None of these choices make a correct statement of Kirchhoff's Junction Rule.
4) I1 - 12 - 13 = 0
5) I1 - 12 + I3 = 0
Part (b) Which statement is a correct expression of Kirchhoff's Loop Rule for the sum of voltage changes for the loop on the
left?
MultipleChoice :
1) IR1 + E1 - 82 + I2R2 = 0
2) -11R1 + E1 + 82 + I2R2 = 0
3) None of these choices make a correct statement.
4) -I1R1 - E1 + E2 + I2R2 = 0
5) IR1 - E1 + E2 - I2R2 = 0
Part (c) Which statement is a correct expression of Kirchhoff's Loop Rule for the sum of voltage changes for the loop on the
right?
MultipleChoice :
1) -I2R2 + E2 - I3R3 - I3R4 + 83 = 0
2) -I2R2 - E2 - I3R3 - I3R4 - 83 = 0
3) None of these choices make a correct statement.
4) -I2R2 - 82 + I3R3 + I3R4 + Ɛ3 = 0
5) -I2R2 - E2 - I3R3 - I3R4 + E3 = 0
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- The capacitor with capacitance C₁ initially carries a charge Q (see figure below). While, the capacitor with capacitance C₂ is initially uncharged. The switch S is closed at time t = 0, and the charges begin to flow in the circuit. Find the charge flown through the wires as a function of time, q(t). QC₁ A) (0) (1 - e-(C₁+C₂)t/RC₁C₂) C₁+C₂ B) (02₂) (1 - e-(C₁+C₂)t/RC₁C₂) C₁+C₂ QC₁ C₂ C) (043) (1 — e¯(C₁+C₂)t/RC₂C₂) D) Q(1 + e-(₁+₂)t/RC1C₂) E) None of the above. +Q C₁ R C₂arrow_forwardAn electric circuit consisting of wires, batteries and resistors is shown. All currents have been labeled and assigned directions. a.) Which statement is a correct expression of Kirchhoff's Junction Rule for currents with labels and directions assigned on the above figure? I1 + I2 + I3 = 0 I1 - I2 + I3 = 0 None of these statements are correct. I1 - I2 - I3 = 0 I1 + I2 - I3 = 0 b.) Which statement is a correct expression of Kirchhoff's Loop Rule for the sum of voltage changes for the large outer loop? 18.0 V - (80.0 Ω)I1 + 12.0 V + (50.0 Ω)I3 + (80.0 Ω)I3 = 0 18.0 V - (80.0 Ω)I1 - 12.0 V + (50.0 Ω)I3 + (80.0 Ω)I3 = 0 None of these statements are correct. 18.0 V - (80.0 Ω)I1 + 12.0 V - (50.0 Ω)I3 - (80.0 Ω)I3 = 0 -18.0 V - (80.0 Ω)I1 - 12.0 V + (50.0 Ω)I3 + (80.0 Ω)I3 = 0 18.0 V - (80.0 Ω)I1 - 12.0 V - (50.0 Ω)I3 - (80.0 Ω)I3 = 0arrow_forward
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