
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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2. The battery voltage is V = 63.2 V; and the resistances are R1 = 53 Ohms; R2 = 122 Ohms; R3 = 104 Ohms; R4 = 102 Ohms; R5 = 111 Ohms; and R6 = 124 Ohms. How much current flows through resistor R3?
0.263 A |
0.215 A |
0.239 A |
0.166 A
|
![The image illustrates an electrical circuit featuring a combination of series and parallel resistors. Here's an explanation suitable for an educational context:
**Description of the Circuit:**
- **Power Source (V):** The circuit is powered by a voltage source denoted as "V".
- **Series Resistors:**
- **R1** and **R2** are connected in series with the voltage source. This means that the same current flows through both resistors, and their resistances add up directly.
- **Parallel Resistors:**
- **R3** is connected in series with the parallel combination of **R4**, **R5**, and **R6**.
- **R4** and **R5** are connected in parallel to each other. This arrangement allows the current to split between these two resistors, and the equivalent resistance can be calculated using the formula for parallel resistors:
\[
\frac{1}{R_{\text{parallel}}} = \frac{1}{R4} + \frac{1}{R5}
\]
- **Additional Series Resistor (R6):**
- **R6** is connected in series with the parallel combination of **R4** and **R5**. This configuration dictates that the total resistance in this branch is the sum of R6 and the equivalent resistance of R4 and R5 in parallel.
**Overall Circuit Analysis:**
To analyze this circuit, one would:
1. Calculate the equivalent resistance of R4 and R5 in parallel.
2. Add this equivalent resistance to R6 to find the total resistance of that branch.
3. Add this total to R3 to address the series combination.
4. Calculate the total resistance of the circuit by adding the resistances of R1, R2, and the series combination found in step 3.
This setup exemplifies a typical circuit problem involving both series and parallel resistive components, demonstrating concepts such as Ohm's Law and the rules for combining resistances.](https://content.bartleby.com/qna-images/question/928fc9f4-b22e-43a8-97be-4ba3df337b27/a009ba3f-277e-4c2f-85b4-8c2436e86623/fz5kjj_thumbnail.png)
Transcribed Image Text:The image illustrates an electrical circuit featuring a combination of series and parallel resistors. Here's an explanation suitable for an educational context:
**Description of the Circuit:**
- **Power Source (V):** The circuit is powered by a voltage source denoted as "V".
- **Series Resistors:**
- **R1** and **R2** are connected in series with the voltage source. This means that the same current flows through both resistors, and their resistances add up directly.
- **Parallel Resistors:**
- **R3** is connected in series with the parallel combination of **R4**, **R5**, and **R6**.
- **R4** and **R5** are connected in parallel to each other. This arrangement allows the current to split between these two resistors, and the equivalent resistance can be calculated using the formula for parallel resistors:
\[
\frac{1}{R_{\text{parallel}}} = \frac{1}{R4} + \frac{1}{R5}
\]
- **Additional Series Resistor (R6):**
- **R6** is connected in series with the parallel combination of **R4** and **R5**. This configuration dictates that the total resistance in this branch is the sum of R6 and the equivalent resistance of R4 and R5 in parallel.
**Overall Circuit Analysis:**
To analyze this circuit, one would:
1. Calculate the equivalent resistance of R4 and R5 in parallel.
2. Add this equivalent resistance to R6 to find the total resistance of that branch.
3. Add this total to R3 to address the series combination.
4. Calculate the total resistance of the circuit by adding the resistances of R1, R2, and the series combination found in step 3.
This setup exemplifies a typical circuit problem involving both series and parallel resistive components, demonstrating concepts such as Ohm's Law and the rules for combining resistances.
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