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Questions 10 - 11 refer to the following information: Planetary Data of Solar System Distance from the Sun (billion meters) Planet Orbital Period (Earth years) Mercury Earth Mars 57.9 149.6 227.9 0.241 1.0 1.88 Saturn 29.5 Uranus 2,870 20,000 84.0 Planet X Y The chart above shows our Solar System's planetary data applied to the Kepler's Third Law, which states that the square of the period of any planet is proportional to the cube of its distance from the Sun. For any planets in the Solar System, the square of the orbital period divided by the cube of its distance from the Sun should be a constant. 10. If Saturn has the period of 29.5 Earth years, find its distance from the Sun, in billion meters? (Round your answer to the nearest whole number.) 11. If Planet X is 20,000 billion meters away from the Sun, what is its orbital period, in Earth years? (Round your answer to the nearest whole number.)

Questions 10 - 11 refer to the following information: Planetary Data of Solar System Distance from the Sun (billion meters) Planet Orbital Period (Earth years) Mercury Earth Mars 57.9 149.6 227.9 0.241 1.0 1.88 Saturn 29.5 Uranus 2,870 20,000 84.0 Planet X Y The chart above shows our Solar System's planetary data applied to the Kepler's Third Law, which states that the square of the period of any planet is proportional to the cube of its distance from the Sun. For any planets in the Solar System, the square of the orbital period divided by the cube of its distance from the Sun should be a constant. 10. If Saturn has the period of 29.5 Earth years, find its distance from the Sun, in billion meters? (Round your answer to the nearest whole number.) 11. If Planet X is 20,000 billion meters away from the Sun, what is its orbital period, in Earth years? (Round your answer to the nearest whole number.)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.7: Applied Problems
Problem 20E
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Answer qs 11
Questions 10 – 11 refer to the following information: Planetary Data of Solar System Distance from the Sun (billion meters) Planet Orbital Period (Earth years) Mercury 57.9 0.241 Earth Mars 149.6 1.0 227.9 1.88 Saturn Uranus 29.5 2,870 84.0 Y Planet X 20,000 The chart above shows our Solar System's planetary data applied to the Kepler's Third Law, which states that the square of the period of any planet is proportional to the cube of its distance from the Sun. For any planets in the Solar System, the square of the orbital period divided by the cube of its distance from the Sun should be a constant. 10. If Saturn has the period of 29.5 Earth years, find its distance from the Sun, in billion meters? (Round your answer to the nearest whole number.) 11. If Planet X is 20,000 billion meters away from the Sun, what is its orbital period, in Earth years? (Round your answer to the nearest whole number.)
Transcribed Image Text:Questions 10 – 11 refer to the following information: Planetary Data of Solar System Distance from the Sun (billion meters) Planet Orbital Period (Earth years) Mercury 57.9 0.241 Earth Mars 149.6 1.0 227.9 1.88 Saturn Uranus 29.5 2,870 84.0 Y Planet X 20,000 The chart above shows our Solar System's planetary data applied to the Kepler's Third Law, which states that the square of the period of any planet is proportional to the cube of its distance from the Sun. For any planets in the Solar System, the square of the orbital period divided by the cube of its distance from the Sun should be a constant. 10. If Saturn has the period of 29.5 Earth years, find its distance from the Sun, in billion meters? (Round your answer to the nearest whole number.) 11. If Planet X is 20,000 billion meters away from the Sun, what is its orbital period, in Earth years? (Round your answer to the nearest whole number.)
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Note: As requested by the user only Question number 11 is solved.

Given:

  • Distance of planet Mercury from the sun is, d=57.9 billion meters.
  • Orbital Period of planet Mercury is, p=0.241 Earth years.
  • Distance of planet X from the sun is 20,000 billion meters.
  • The square of the orbital period divided by the cube of the distance from the Sun should be a constant.

The objective is to find the orbital period of the planet X, in Earth years.

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