QUESTION Which of the following functions fails to satisfy the conditions of the Mean Value Theorem f(x) = x2 – 4 on [0, 2] %3D f(x) = |x| on [- 1, 1]. f(x) = x on [0,2].

Q4. Please help with this problem - thank you!

Find the values of c guaranteed by the Mean Value Theorem (MVT) for f(x) = 10 x over the interval [10, 10]. In other words, find c E [10, 10] such that f(c) This function has two values, c₁ and c₂, where c₁ < C₂. 41 = 10 10-11-10) / 10 -10) / f(x)dx. - 10 - C2

Let f(x) = 2 – |2x – 1|. Show directly that there is no value of c in the Why does this not contract the Mean Value f(3)-f(0) interval (0, 3) so that f'(c) Theorem? Does your answer change if f(x) = 2 – |2x – 6|? Why or why not? 3-0