Question: The project flow rate determined according to the stream yield will be transmitted through a rectangular channel in the shape of Q = 10 m3/s. The Manning coefficient was determined as n = 0.04 according to the covering material of the channel and the longitudinal base slope of the channel was determined as 10 = 0.0015 according to the topographic characteristics of the land. Determine the channel bottom width (B) and flow depth (h) with the concept of the most appropriate cross section.

Question: The project flow rate determined according to the stream yield will be transmitted through a rectangular channel in the shape of Q = 10 m3/s. The Manning coefficient was determined as n = 0.04 according to the covering material of the channel and the longitudinal base slope of the channel was determined as 10 = 0.0015 according to the topographic characteristics of the land. Determine the channel bottom width (B) and flow depth (h) with the concept of the most appropriate cross section.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Hydrology-SLOPE-AREA METHOD During a flood flow the depth of water in a 12 m wide rectangular channel was found to be 3.5 m and 3.0 m at two sections 300 m apart. The drop in the water-surface elevation was found to be 0.15 m. Assuming Manning’s coefficient to be 0.025, estimate the flood discharge through the channel.
(b) A channel is to be designed for carrying a discharge of 50 m/s, side slope 0.5:1 and silt factor 1.0. Calculate the longitudinal slope of the channel also.
Consider a farm irrigation ditch in a loam soil having the following dimensions: bottom width,0.5m; total depth, 0.6 m; side slopes of 1horizontal to 1 vertical, and depth of water, 0.4 m.The bottom of the ditch has a uniform slope of 1 m/km. Assume a Manning’s roughnesscoefficient, n of 0.02 Find the mean velocity of flow. ANSWER SHOULD BE 0.58 m/s
For #5-7, assume there is a creek with a width of 4.6 m, depth of 23 cm, slope of 0.001 m/m, and discharge of 0.13 m³/s. 5. Assuming a rectangular cross section, what is the hydraulic radius of the creek to the nearest cm? 6. What is the average flow velocity to the nearest cm/s? 7. And what is the channel's Manning's roughness coefficient (using SI units) to the nearest hundredth?
A concrete-lined trapezoidal channel has to be constructed to carry a discharge of 500 cfs.Design the channel. Assume that the following values were fixed based on the siteconditions:1. Bed slope = 0.0022. n = 0.0153. Side slope, z = 1 (vertical):1.5 (horizontal)4. b/y ratio = 2.0
1 2 3 4 6 6 6 6 7 6 9 Dimensions in the figure are in meters. With the given dimensions and Manning coefficients, determine the channel's flow rate and the channel's effective Manning coefficient. Water is flowing on a channel whose bottom slope is 0.002. The cross-section of the channel is shown in the figure. The channel has an unfinished cement surface (n = 0.014) at subsections 1 and 2 and a light brush (n = 0.05) at subsection 3. 9
Question 4 The flow rate in a wide rectangular channel is 5.0m³/sec/m. The channel bed slope is 0.0035. The manning's coefficient is 0.016. The slope of channel is classified as-
A trapezoidal channel conveys a flow of 11.00m:/s. The channel has a side slope ratio of 1.70:1 (horizontal to l vertical), a bottom width of 4.40m and the Manning's coefficient is 0.022m-/8s. If the normal depth of flow is 1.00m, estimate the slope of the channel. Please keep four decimal points (i.e. to the accuracy of 0.0001)
6. A 3.6 m wide rectangular channel carries water to a depth of 1.8 m. In order to measure the discharge, the channel width is reduces to 2.4 m and a hump of 0.30 m height is provided in the bottom. Calculate the discharge if water surface in the contracted section IQ-6.418 m/s] drops by 0.15 m. Assume no losses.
Q3/ A Trapezoidal open channel. The following data are available:- 1- Cross -sectional area of flow in the channel A = 75 (m). 2- Wetted perimeter of the channel P = 100 (m). 3- Longitudinal slope of bed level of the channel S, = 0.0001 4- Bed width of the channel B = 10 (m). %3D 5- Width of channel at water level W = 2B (1/3) 6- n = 0.025 {S/mu/3)} Find:- 1- Flow rate in the channel Q. 2- Side Slope of the channel Z. 3- Fluids Number Fr. 4- Type of flow in the channel.
PROBLEM 3 SLOPE-AREA METHOD During a flood flow the depth of water in a 12 m wide rectangular channel was found to be 3.5 m and 3.0 m at two sections 300 m apart. The drop in the water-surface elevation was found to be 0.15 m. Assuming Manning's coefficient to be 0.025, estimate the flood discharge through the channel.
4.61. Water flows at 11 m³/s in a rectangular channel of width 5 m. The slope of the channel is 0.1% and the Manning roughness coefficient is equal to 0.035. If the depth of flow at a selected section is 2 m, calculate the upstream depths at 20 m intervals along the channel until the depth of flow is within 5% of the uniform flow depth.