Question Find the particular solution to the differential equation below given that y(0) = -5π. y' = 2π sec² (πx) Be sure to put the arguments of any trigonometric functions in parentheses. × Not quite - review the answer explanation to help get the next one. y= -5л

tion for the equation Ghana is currently be worth in 10 years? I COS I + c (b) GHC410.55/acre (c) GHC510.65/acre (d) GHC500.25/acre (e) None of the above 29. It is estimated that r years from now, the value of an acre of farmland will be increasing at a rate of 0.473 (sin? x)(sin? 2u) Cedis each year. If the Y.3+ 800 GHS 500 per an acre, how much will it (a) GHC110.55/acre COs I-I+ C e value of b e tion

Solve the equation 6sin^2x − cosx − 5 = 0 for. x ∈ [0, 2π].Round answers to 2 decimals.

Two derivations of the identity sec¬1(-x) = # – sec-lx a. (Geometric) Here is a pictorial proof that sec-'(-x) = T - sec-lx. See if you can tell what is going on. y = sec-lx х b. (Algebraic) Derive the identity sec¬'(-x) = T – sec-lx by combining the following two equations from the text: cos(-x) = T – cosx Eq. (4), Section 1.6 sec-lx = cos'(1/x) Eq. (1)

-1 cosh -1 5x = sinh 4x.

S- 10* -dx may be written as Aln secB* + tanB* +C. where A, B, and Care constants not equal to zero. Evaluate the value of cos10 22. +B А. О В. 15 C. 20 D. -20

solve for y=3 (Find all solutions)  y = 2+5cos((pi/7)(x+1))

A rescued whale is released into the ocean 400 meters due east of a coast guard station. The whale swims directly away from the shore. coast guard station point of release O tan(0) (a) Which of the following equations can be used to relate the angle, 0, and the distance between the whale and the point of release, x? O cos(0) O sec(0) = O sin(0) = O tan(0) = X 400 X 400 X 400 O cos² (0)- X 400 400 X O sec² (8) de dt de dt (b) Which of the following would be an appropriate related rate equation for the answer to part (a)? 1 dx 400 dt = O sec² (0) dx dt O sec(0)tan(0)- O cos²(e) de dt = = 8 1 dx 400 dt de 1 dx dt 400 dt = dx dt X whale 1 de 400 dt (c) If the whale swims at a constant rate of 60 meters per minute, how fast is the angle changing when the whale is 300 meters from the point of release? Give an exact answer. radians per minute

The height at time t (in seconds) of a mass, oscillating at the end of a spring, is s(t) = 300 + 42 sin(t) cm Find the velocity and acceleration at t = S. (Use symbolic notation and fractions where needed.) v(t) cm/s cm/s2 a(t)

sketch and solve for y = 0 (a) y = -2 + 5sin((pi/7)(x+1)) b. y = 3 + 4cos((1/5)(x-1))