Question : By using Python Programming Language, Plot two simple bar diagrams showing the average reaction times with their standard deviations (error bars) of the total ‘match’ trials and the ‘false alarm’ trials respectively from given below input text data file. Text.txt File Data is given Below. Please save it as Text.txt file name : 1 1 0 1 0 0 0 3000 3 8 8 0 1 2 0 1 0 0 0 3000 2 2 2 8 1 3 0 1 0 0 0 3000 3 3 3 2 1 4 0 1 0 0 0 3000 2 1 1 3 1 5 0 1 0 0 0 3000 2 11 11 1 1 6 1 1 1 0 0 469 1 1 1 11 1 7 0 1 0 0 0 3000 2 2 2 1 1 8 0 1 0 0 0 3000 2 14 14 2 1 9 0 1 0 0 0 3000 3 8 8 14 1 10 1 1 1 0 0 610 1 14 14 8 1 11 0 1 0 0 0 3000 3 4 4 14 1 12 0 1 0 0 0 3000 2 15 15 4 1 13 1 1 1 0 0 520 1 4 4 15 1 14 1 1 1 0 0 1723 1 15 15 4 1 15 0 1 0 0 0 3000 2 8 8 15 1 16 1 1 1 0 0 983 1 15 15 8 1 17 0 1 0 0 0 3000 2 11 11 15 1 18 0 1 0 0 0 3000 2 1 1 11 1 19 1 1 1 0 0 613 1 11 11 1 1 20 1 1 1 0 0 885 1 1 1 11 1 21 0 1 0 0 0 3000 2 8 8 1 1 22 0 1 0 0 0 3000 2 8 8 8 1 23 0 1 0 0 0 3000 3 10 10 8 1 24 0 1 0 0 0 3000 2 9 9 10 1 25 0 1 0 0 0 3000 2 5 5 9 2 1 0 1 0 0 0 3000 2 12 12 5 2 2 0 1 0 0 0 3000 3 12 12 12 2 3 1 1 1 0 0 671 1 12 12 12 2 4 0 1 0 0 0 3000 2 1 1 12 2 5 0 1 0 0 0 3000 3 15 15 1 2 6 0 1 0 0 0 3000 2 4 4 15 2 7 0 1 0 0 0 3000 2 4 4 4 2 8 0 1 0 0 0 3000 3 12 12 4 2 9 0 1 0 0 0 3000 2 1 1 12 2 10 0 1 0 0 0 3000 2 1 1 1 2 11 0 1 0 0 0 3000 2 15 15 1 2 12 1 1 1 0 0 608 1 1 1 15 2 13 0 1 0 0 0 3000 3 7 7 1 2 14 0 1 0 0 0 3000 3 7 7 7 2 15 1 1 1 0 0 432 1 7 7 7 2 16 0 1 0 0 0 3000 3 1 1 7 2 17 0 1 0 0 0 3000 2 6 6 1 2 18 1 1 1 0 0 442 1 1 1 6 2 19 1 1 1 0 0 710 1 6 6 1 2 20 0 0 0 0 1 2166 2 6 6 6 2 21 0 1 0 0 0 3000 2 13 13 6 2 22 0 1 0 0 0 3000 2 7 7 13 2 23 0 1 0 0 0 3000 3 1 1 7 2 24 0 1 0 0 0 3000 3 13 13 1 2 25 1 1 1 0 0 574 1 1 1 13 3 1 0 1 0 0 0 3000 2 4 4 1 3 2 0 1 0 0 0 3000 1 13 13 4 3 3 0 1 0 0 0 3000 2 6 6 13 3 4 1 0 0 1 0 3000 1 13 13 6 3 5 1 1 1 0 0 411 1 6 6 13 3 6 0 1 0 0 0 3000 2 4 4 6 3 7 0 1 0 0 0 3000 3 15 15 4 3 8 0 1 0 0 0 3000 2 15 15 15 3 9 0 1 0 0 0 3000 2 12 12 15 3 10 0 1 0 0 0 3000 2 2 2 12 3 11 0 1 0 0 0 3000 3 13 13 2 3 12 0 1 0 0 0 3000 3 6 6 13 3 13 1 1 1 0 0 437 1 13 13 6 3 14 0 1 0 0 0 3000 2 9 9 13 3 15 0 1 0 0 0 3000 3 15 15 9 3 16 1 1 1 0 0 1030 1 9 9 15 3 17 0 1 0 0 0 3000 2 6 6 9 3 18 0 1 0 0 0 3000 2 8 8 6 3 19 0 1 0 0 0 3000 3 11 11 8 3 20 1 1 1 0 0 1252 1 8 8 11 3 21 0 1 0 0 0 3000 3 8 8 8 3 22 0 1 0 0 0 3000 3 14 14 8 3 23 0 1 0 0 0 3000 2 6 6 14 3 24 0 1 0 0 0 3000 2 7 7 6 3 25 0 1 0 0 0 3000 2 9 9 7
Question : By using Python Programming Language, Plot two simple bar diagrams showing the average reaction times with their standard deviations (error bars) of the total ‘match’ trials and the ‘false alarm’ trials respectively from given below input text data file.
Text.txt File Data is given Below. Please save it as Text.txt file name :
1 1 0 1 0 0 0 3000 3 8 8 0
1 2 0 1 0 0 0 3000 2 2 2 8
1 3 0 1 0 0 0 3000 3 3 3 2
1 4 0 1 0 0 0 3000 2 1 1 3
1 5 0 1 0 0 0 3000 2 11 11 1
1 6 1 1 1 0 0 469 1 1 1 11
1 7 0 1 0 0 0 3000 2 2 2 1
1 8 0 1 0 0 0 3000 2 14 14 2
1 9 0 1 0 0 0 3000 3 8 8 14
1 10 1 1 1 0 0 610 1 14 14 8
1 11 0 1 0 0 0 3000 3 4 4 14
1 12 0 1 0 0 0 3000 2 15 15 4
1 13 1 1 1 0 0 520 1 4 4 15
1 14 1 1 1 0 0 1723 1 15 15 4
1 15 0 1 0 0 0 3000 2 8 8 15
1 16 1 1 1 0 0 983 1 15 15 8
1 17 0 1 0 0 0 3000 2 11 11 15
1 18 0 1 0 0 0 3000 2 1 1 11
1 19 1 1 1 0 0 613 1 11 11 1
1 20 1 1 1 0 0 885 1 1 1 11
1 21 0 1 0 0 0 3000 2 8 8 1
1 22 0 1 0 0 0 3000 2 8 8 8
1 23 0 1 0 0 0 3000 3 10 10 8
1 24 0 1 0 0 0 3000 2 9 9 10
1 25 0 1 0 0 0 3000 2 5 5 9
2 1 0 1 0 0 0 3000 2 12 12 5
2 2 0 1 0 0 0 3000 3 12 12 12
2 3 1 1 1 0 0 671 1 12 12 12
2 4 0 1 0 0 0 3000 2 1 1 12
2 5 0 1 0 0 0 3000 3 15 15 1
2 6 0 1 0 0 0 3000 2 4 4 15
2 7 0 1 0 0 0 3000 2 4 4 4
2 8 0 1 0 0 0 3000 3 12 12 4
2 9 0 1 0 0 0 3000 2 1 1 12
2 10 0 1 0 0 0 3000 2 1 1 1
2 11 0 1 0 0 0 3000 2 15 15 1
2 12 1 1 1 0 0 608 1 1 1 15
2 13 0 1 0 0 0 3000 3 7 7 1
2 14 0 1 0 0 0 3000 3 7 7 7
2 15 1 1 1 0 0 432 1 7 7 7
2 16 0 1 0 0 0 3000 3 1 1 7
2 17 0 1 0 0 0 3000 2 6 6 1
2 18 1 1 1 0 0 442 1 1 1 6
2 19 1 1 1 0 0 710 1 6 6 1
2 20 0 0 0 0 1 2166 2 6 6 6
2 21 0 1 0 0 0 3000 2 13 13 6
2 22 0 1 0 0 0 3000 2 7 7 13
2 23 0 1 0 0 0 3000 3 1 1 7
2 24 0 1 0 0 0 3000 3 13 13 1
2 25 1 1 1 0 0 574 1 1 1 13
3 1 0 1 0 0 0 3000 2 4 4 1
3 2 0 1 0 0 0 3000 1 13 13 4
3 3 0 1 0 0 0 3000 2 6 6 13
3 4 1 0 0 1 0 3000 1 13 13 6
3 5 1 1 1 0 0 411 1 6 6 13
3 6 0 1 0 0 0 3000 2 4 4 6
3 7 0 1 0 0 0 3000 3 15 15 4
3 8 0 1 0 0 0 3000 2 15 15 15
3 9 0 1 0 0 0 3000 2 12 12 15
3 10 0 1 0 0 0 3000 2 2 2 12
3 11 0 1 0 0 0 3000 3 13 13 2
3 12 0 1 0 0 0 3000 3 6 6 13
3 13 1 1 1 0 0 437 1 13 13 6
3 14 0 1 0 0 0 3000 2 9 9 13
3 15 0 1 0 0 0 3000 3 15 15 9
3 16 1 1 1 0 0 1030 1 9 9 15
3 17 0 1 0 0 0 3000 2 6 6 9
3 18 0 1 0 0 0 3000 2 8 8 6
3 19 0 1 0 0 0 3000 3 11 11 8
3 20 1 1 1 0 0 1252 1 8 8 11
3 21 0 1 0 0 0 3000 3 8 8 8
3 22 0 1 0 0 0 3000 3 14 14 8
3 23 0 1 0 0 0 3000 2 6 6 14
3 24 0 1 0 0 0 3000 2 7 7 6
3 25 0 1 0 0 0 3000 2 9 9 7
Step by step
Solved in 2 steps with 1 images
