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- Use the data provided below to calculate the lattice energy of RbCl. Is this value greater or less than thelattice energy of NaCl? Explain.Electron affinity of Cl = –349 kJ/mol1st ionization energy of Rb = 403 kJ/molBond energy of Cl2 = 242 kJ/molSublimation energy of Rb = 86.5 kJ/molΔHf [RbCl (s)] = –430.5 kJ/mol1) Calculate the lattice energy for NaCl(s) using a Born-Haber cycle and the following information: NaCl(s) → Nat(g) + Cl-(g) Na(s) + 1/2 C12(g) → NaCl(s) Na(s) → Na(g) Na(g) → Na+(g) + e- 1/2 C12(g) → Cl(g) Cl(g) + e- → Cl-(g) ? -411.0 kJ/mol +107.3 kJ/mol +495.8 kJ/mol +121.7 kJ/mol -348.6 kJ/molConsider the A2X4 molecule depicted here, where A and X are elements. The A – A bond length in this molecule is d1, and the four A – X bond lengths are each d2 (a) In terms od d1 and d2, how could you define the bonding atomic radii of atoms A and X? (b) In terms of d1 and d2, what would you predict for the X-X bond length of an X2 molecule?
- Given: Enthalpy of atomisation of calcium =+ 178 kJ First ionisation energy of calcium =+590 kJ Second ionisation energy of calcium = +1145 kJ Enthalpy of atomisation of chlorine =+ 121 kJ Electron affinity of chlorine Lattice energy of calcium chloride =- 2258 kJ = - 346 kJ Construct a Born-Haber cycle for calcium chloride, CaCl2 by using the data given above. Hence, calculate the enthalpy of formation of calcium chloride. b. The enthalpy of solution for calcium chloride crystal is -81.3 kJ mol'. Based on the data from the above Born-Haber cycle, calculate the enthalpy change for the reaction below: Ca" (g) + 2CI (g)–→ Ca* (aq) + 2CI¯ (aq)Although it is helpful to know that many ions have the electronarrangement of a noble gas, many elements, especially among themetals, form ions that do not have a noble-gas electron arrangement.Use the periodic table, Figure 2.14, to determine which ofthe following ions has a noble-gas electron arrangement, andwhich do not. For those that do, indicate the noble-gas arrangementthey match: (a) Ti4+, (b) Mn2+, (c) Pb2+, (d) Te2- , (e) Zn2+.Item 5 Answer the following questions related to the chemical bonding in substances containing Cl. (a) What type of chemical bond is present in the Cl2 molecule? (b) Cl2 reacts with the element Sr to form an ionic compound. Based on periodic properties, identify a molecule, X2, that is likely to react with Sr in a way similar to how Cl2 reacts with Sr. Justify your choice. (c) A graph of potential energy versus internuclear distance for two Cl atoms is given below. On the same graph, carefully sketch a curve that corresponds to potential energy versus internuclear distance for two Br atoms. (d) In the box below, draw a complete Lewis electron-dot diagram for the C2Cl4 molecule. (e) Answer the following based on the diagram you drew above. (i) What is the hybridization of the CC atoms in C2Cl4? (ii) What is the approximate chlorine-carbon-chlorine bond angle in C2Cl4? (iii) Is the C2Cl4 molecule…
- Without consulting any tables, arrange the following sub- stances in order and explain your choice of order: (a) Mg²+, Ar, Br¯, Ca²* in order of increasing radius (b) Na, Na*, O, Ne in order of increasing ionization energy (c) H, F, Al, O in order of increasing electronegativityUse the periodic table to (i) predict electron configurations for the following species: Arsenic ion, As3– Magnesium ion, Mg2+ Vanadium(II) ion, V2+ (ii) Write the electron configurations of each species in the noble gas notation. (iii) Draw an orbital diagram to represent 1 c above. Draw the Lewis electron dot structures of the following chemical species. In each case you must say whether or not the central atom obeys the Octet Rule. CS2 and H2S CF4 and SiH4 NH2Cl CO32– and BF3 PCl5 ClF3, XeF2, Calculate the formal charge on the Sulphur atom in the Sulphate anion structure shown below(picture attatched) Give the electron-pair and molecular geometries for NF3 and XeF4.Calculate the lattice energy of NaBr(s), given the following thermochemical equations, where A/E and AEA are ionization energy and electron affinity, respectively. Na(s)Na(g) AH = +107 kJ Na(g) Nat(g) + e A/E = +496 kJ -> 1/2 Br₂(g) → Br(g) AHf = +112 kJ - Br(g) + e¯ → Br¯(g) AEA = -325 kJ Na(s) + 1/2 Br₂(g) → NaBr(s) AH = -361 kJ ->> - -1401 kJ -751 kJ +29 kJ -29 kJ +751 kJ
- 2. Which one of each of the following pairs has the higher ionization energy? Explain in detail for each case. (a) Na or K (b) Ве or B (с) В or C (d) N or O F or Ne (f) Mg or Mg* Ne or NaThe lattice energy of potassium iodide is the energy required for the following reaction. KI(s) → K+(g) + I−(g) ΔHrxn = ΔHlattice Use the Born-Haber cycle to calculate ΔHlattice for KI(s) from the information given below. Equation 1: 2 K(s) + I2(g) → 2 KI(s) ΔH1 = −655 kJ/mol Equation 2: K(s) → K(g) ΔH2 = 89 kJ/mol Equation 3: I2(g) → 2 I(g) ΔH3 = 214 kJ/mol Equation 4: K(g) → K+(g) + e− ΔH4 = 419 kJ/mol Equation 5: I(g) + e− → I−(g) ΔH5 = −294 kJ/molPredict the chemical formulas of the compounds formed bythe following pairs of ions: (a) Fe3+ and O2- , (b) NH4+ and PO43-(c) Ag and N , (d) Ca and Br, (e) Sr and Cl