
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:QUESTION 11
A voltaic cell (same as a galvanic cell) is created from a Cu/Cu<* half-cell (E°red = +0.34 V) and an
2+
Al/AI3+
AI/AIS+
half-cell (Ered = -1.66 V). Calculate the value of AG for this cell.
O A. -1.16 x 10
B. -193000 J
C. -764000 J
D.-1158000kJ
E. 193000 J
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- Question 2 Calculate the cell potential of the following voltaic cell. Zn/Zn²+ (0.001 M)||Cu²+ (0.0001 M) Cu a. +1.22 V O b. +0.98 V O c. +1.04 V d. +1.07 V e. +1.10 Varrow_forwardPlease help chemistryarrow_forwardWhich of the following statements is true concerning the voltaic cell shown below? Voltmeter Kt NO,- Cu+ Zn* NO, So, Zn Cu So, NO, NO, Zn Cut II O a. Zn is the anode having a mass that increases with time. O b. Zn is the cathode having a mass that decreases with time Oc The mass of the Zn electrode neither increases nor decreases with time. O d. Zn is the anode having a mass that decreases with time. O e. Zn is the cathode having a mass that increases with time.arrow_forward
- The two redox half reactions represented below are combined to create a galvanic cell. Which statements are true regarding this cell? Select all that apply. 2 H+ (aq) + 2 e= H₂(g) Eº = 0.00 V La³+ (aq) + 3 e La(s) Eº = -2.38 V Three electrons are transferred in the overall, balanced reaction for the cell. La³+ is reduced to La(s) at the cathode. The overall, standard cell potential is 2.38 V. La³+ is produced at the anode. H₂(g) is produced at the cathode. La(s) is the oxidizing agent.arrow_forwardFor the voltaic cell, A/B Ecell = 0.4V A is connected to the black electrode (A/A²+):(B/B²+) What is the reduction equation for this cell? A. B²+ + 2e → B B. B B²+ + 2e C. A²+ + 2e. → A D. A → A²+ + 2e E. none of thesearrow_forwardFind the FALSE statement about the voltaic cell based on the two reduction half- reactions shown below. The concentrations of the ions are [Al3+] = 0.01 M, [Mn2*] = 0.1 M. A13+(aq) + 3e¯ - Al(s) E°red = -1.66 V Mn2+(aq) + 2e - Mn(s) E°red = -1.18 V Al(s) is a stronger reducing agent than Mn(s) The observed cell potential is 0.49V For the balanced equation, n = 6 and Q = [AI³+]/ [Mn2+]. Using base 10, logQ = -1. The shorthand diagram for this cell is Al(s) | AI3*(aq) || Mn²*(aq) | Mn(s).arrow_forward
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