Question A donut shop that specializes in unique donuts made from potatoes wants to learn more about their business costs. Past data reveals that the cost for fifty pounds of potatoes has a mean of $75 with standard deviation $13. The normal distribution for the population is shown by the dotted black line. The donut shop plans to take a random sample of 31 such fifty pound bags of potatoes and will calculate the mean cost of the sample to compare to the known cost. Compute the mean and standard deviation of the sampling distribution of sample means for a sample of size 31. Round your answers to the nearest tenth. Show your answer by moving the two draggable points to build the sampling distribution. Sorry, that's incorrect. Try again? -0-2- -0-15- -0-1- 0:05- 60 The population has a normal distribution- with mean 75 and standard deviation 13. 65 70 75 75 80 85 90

It is generally believed that there is a relationship between a college’s acceptance rate and its graduation rate. I wanted to know how strong this relationship is within the top universities in the country so I collected the graduation rate and acceptance rate data of a randomly selected sample of universities from all the top U.S. universities (with an acceptance rate at or below 30%). The data set is in Tab Q2 of the Excel data file. a.) Create a scatter plot between the two variables using Excel. Paste the plot here and format it into an APA-styled “figure” (see Assignment Guides for APA format).Be sure to submit the Excel file that you used to create the scatter plot.     b) Calculate the mean and standard deviation for the two variables separately.   c) Calculate the Z scores for all the scores of the two variables, separately.Tips: It may help to prevent error and to increase clarity if the process and/or the answers (z scores) are listed in a table format.     d) Calculate…

It is often quoted that in a normal distribution, 95% of the data lies 1.96 deviations either side of the mean. How many deviations from the mean would 88 percent lie?

Over the first five years of owning her car, Gina drove about 12,700 miles the first year, 15,478 miles the second year, 12,675 the third year, 11,850 the fourth year, and 13,075 the fifth year. a. Find the mean, median, and mode of this data. b. Explain which measure of central tendency will best predict how many miles Gina will drive in the sixth year. a. mean= 12,700; median= 13,156; no mode; the mean is the best choice because it is representative of the entire data set. b. mean= 13,156; median= 12,700; mode= 3,628; the median is the best choice because it is not skewed by the high outlier. c. mean= 13,156; median= 12,700; no mode; the mean is the best choice because it is representative of the entire data set. d. mean= 13,156; median= 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.