Question 8 Based on a quality control report, the weights of cereal boxes coming out of the production line are normally distributed with a mean of 60.4 oz and a standard deviation of 1.5 oz. Let X be the weight of a randomly selected cereal box. 1. Describe the probability distribution of X and state its parameters μ and σ: X - Select an answer ( Select an answer ZNF BT σ 2. Find the probability that the weight of a randomly selected cereal box is a. less than 58.1 oz. b. between 61.7 and 64.9 oz. c. more than 58.4 oz. (Round the answer to 4 decimal places) (Round the answer to 4 decimal places) (Round the answer to 4 decimal places) 3. Find the 40-th percentile for the weights of cereal boxes coming out of the production line. (Round the answer to 1 decimal place) oz

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Q: If P(A) = 0.5, P(B|A) = 0.2, P(AUB) = 0.7, then P(B) = 0.7 0.1 0.3 0.2

A: P(A)  = 0.5P(B|A) = 0.2P(A∪B) = 0.7P(B) = ?

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A:

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A:

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A:

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A: The data points from the chart are  1 90 2 96 3 87 4 94 5 89 6 86 7 84 8 85 9 88…

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A: Given  P(A) =0.49, P(B)=0.39

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A:

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A: given data,p(A)=0.9383p(B)=0.0182p(A and B)=0.0081p(A or b)=?

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A: F~F(13,4)

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A: We have given that,  F~F(11, 10)  then we will find the probability,  P(0.6 &lt; F&lt; 3.99) = ?

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A: given data n1 =66x1  =7n2  = 270x2 =49α = 0.08claim : p1 ≠ p2p^1 = x1n1 = 766 = 0.1061p^2 = x2n2  =…

Q: Residuals 100 Plot of residuals vs. predicted values 50- 0- -50- -100- 500 1000 1500 2000

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A: Given information: Value Frequency Proportion Percentage 1 1 0.04 4% 2 2 0.08 8% 3 3 0.12…

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A: We have given that Mean(µ) = 125Standard deviations (σ) = 28.7

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A: given data, 12 % of peanut  brown15 % yellow12 % red 23% blue 23 % orange 15 % green

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A: independent events P(A)  = 0.4326P(B) = 0.1593P(A and B) = ?

Q: Question 3 For a uniform random variable U~ U(1, 11), find the probability P(7<U < 10): P(7<U < 10)…

A: U~U(1,11)

Q: (a < X <b): P(a < X < b) = (Round the answer to 2 decimal places)

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Q: Question 1 Compute P:

A: Here, given that 8P5