QUESTION 8 An electron moves at a velocity of 8.26 x 10^6 m/s in a direction perpendicular to a magnetic field of strength 2.63 T. How much force will the electron experience? 4.52E-12 N

An electron moves at a velocity of 3.05 x 10^6 m/s in a direction perpendicular to a magnetic field of strength 4.89 T. How much force will the electron experience? 4.06E-12 N 2.39E-12 N 1.43E-12 N 3.11E-12 N

9. A helium nucleus (2 protons, 2 neutrons) is traveling at a velocity of 4.33 x 10^6 m/s a distance of 4.52 cm away from a wire carrying a current of 1.40 A. The helium nucleus is traveling in a direction parallel to the current in the wire. How much acceleration does the helium nucleus experience due to the magnetic force from the current in the wire?     1.54E+09 m/s^2   2.05E+09 m/s^2   1.28E+09 m/s^2   5.12E+08 m/s^2

An proton traveling in the -i direction enters a magnetic field directed in the +j direction. What will be the direction of the force acting on the proton due to the magnetic field? +k tî

What is the magnitude of the magnetic force on a charged particle (Q = 5.0 μC) moving with a speed of 80 km/s in the positive x direction at a point where B₂ = 3.0 T? a. b. C. d. e. 2.8 N 1.6 N 1.2 N 2.0 N 0.4 N