College Physics
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ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![### QUESTION 7
**What is the average translational kinetic energy of an ideal gas at 816 K? (The value of Boltzmann's constant is \(1.38 \times 10^{-23} \text{ J/K}\))**
- \( \circ \) \( 5.63 \times 10^{-21} \text{ J} \)
- \( \circ \) \( 3.75 \times 10^{-19} \text{ J} \)
- \( \circ \) \( 1.12 \times 10^{-17} \text{ J} \)
- \( \circ \) \( 1.69 \times 10^{-20} \text{ J} \)
**Instructions: Click Save and Submit to save and submit. Click Save All Answers to save all answers.**
### Explanation
This question requires the calculation of the average translational kinetic energy of an ideal gas at a given temperature using the formula:
\[ E_{avg} = \frac{3}{2} k_B T \]
Where:
- \( E_{avg} \) is the average translational kinetic energy,
- \( k_B \) is Boltzmann's constant (\(1.38 \times 10^{-23} \text{ J/K}\)),
- \( T \) is the temperature in Kelvin (816 K).
Substituting the given values:
\[ E_{avg} = \frac{3}{2} \times 1.38 \times 10^{-23} \text{ J/K} \times 816 \text{ K} \]
Evaluating the above expression will give one of the provided options as the correct answer.](https://content.bartleby.com/qna-images/question/8689a897-6f19-4f8c-bce2-bc1e854b9491/ec42b8e0-4577-4413-a3bc-e30eafde15e0/f6692zt.jpeg)
Transcribed Image Text:### QUESTION 7
**What is the average translational kinetic energy of an ideal gas at 816 K? (The value of Boltzmann's constant is \(1.38 \times 10^{-23} \text{ J/K}\))**
- \( \circ \) \( 5.63 \times 10^{-21} \text{ J} \)
- \( \circ \) \( 3.75 \times 10^{-19} \text{ J} \)
- \( \circ \) \( 1.12 \times 10^{-17} \text{ J} \)
- \( \circ \) \( 1.69 \times 10^{-20} \text{ J} \)
**Instructions: Click Save and Submit to save and submit. Click Save All Answers to save all answers.**
### Explanation
This question requires the calculation of the average translational kinetic energy of an ideal gas at a given temperature using the formula:
\[ E_{avg} = \frac{3}{2} k_B T \]
Where:
- \( E_{avg} \) is the average translational kinetic energy,
- \( k_B \) is Boltzmann's constant (\(1.38 \times 10^{-23} \text{ J/K}\)),
- \( T \) is the temperature in Kelvin (816 K).
Substituting the given values:
\[ E_{avg} = \frac{3}{2} \times 1.38 \times 10^{-23} \text{ J/K} \times 816 \text{ K} \]
Evaluating the above expression will give one of the provided options as the correct answer.
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