QUESTION 6 (Fuels and Combustion) The chemical analysis by mass of a fuel is: C = 87.1%, H2 = 4.4%, O2 = 1.2% and ash = 7.3%. Determine the amount of air required for combustion of the fuel.
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- QUESTION 7 (Fuels and Combustion) (a) The volumetric analysis of the flue gases from a boiler consists of CO2 = 10.9%, co = 1%, O2 = 7.1% and N2 = 81.0%. Determine the mass of the flue gas per kg of burnt fuel. (b) The mass analysis of a flue gas is: CO2 = 21.6%, CO = 2.2%, O2 = 1.7% and N2 = 74.5%. Determine the mass of the flue gas per kg of burnt fuel.Not yet answered Question 1 Marked out of 1.00 A sample of coal fuel has the following ultimate analysis, percent by mass: H2 = 5.6% ; C = 53.4% ; S = 0.1% ; N2 = 0.1% ; 02 = 37.9% and Ash = 2.9%. This coal will be used as a fuel by burning it with no excess air in a furnace. Determine the HHV of the fuel in KJ/kg1. How does the presence of Nitrogen in air affect the outcome of a combustion process? How does the presence of moisture in air affect the outcome of a combustion process? and What are the approximate chemical compositions of gasoline, diesel fuel, and natural gas? BoldItalicUnderline
- 1. A bituminous coal has the following composition as follows: C=71.5%, O=6%, S-4.6% W=3.4% H=5% N=1.3% Ash=3.2% Compute the amount of nitrogen produced during combustion process in lb/lb-coal. Also, determine the stoichiometric amount of air present in the combustion.Calculate the minimum volume of air required for the complete combustion of 1 m³ of a gaseous fuel containing the following composition by volume: CO = 25%; H₂ = 10%; CH4 = 8%; CO₂ = 5%; N₂ = 50% and O₂ = 2%C4Hs is burned in an engine with a fuel-rich air-fuel ratio. Dry analysis of the exhaust gives the following volume percents: CO2 = 14.95%, C4H8 0.75%, CO = 0%, H2 = 0%, O2 = 0%, with the rest being N2. Higher heating value of this fuel is QHHV = 46.9 MJ/kg. Write the balanced chemical equation for one mole of this fuel at these conditions. Calculate; a) Air-fuel ratio. b) Equivalence ratio. c) Lower heating value of fuel. [MJ/kg] d) Energy released when one kg of this fuel is burned in the engine with a combustion efficiency of 98%. [MJ]
- Given the ultimate/gravimetric analysis of coal as follows: C=81.95%, H2 = 4.63%, S=0.96%, N2=1.3%, O2=5.75%, Ash=6.09%, Moisture = 3.05% Using ash and moisture free analysis. Determine the; molecular weight of the fuel 45 mins left please help meProblem 4) LHV and HHV of Fuels Consider the following list of some fuels with their LHV and HHV. a) Provide a plot of the LHV as a function of the molecular mass of the fuel. Group the fuels in categories and discuss any correlation between the heating values and the molecular mass. b) Provide a plot of the percentage increase of the HHV relative to the LHV as a function of the molecular mass of the fuel. Discuss any correlation or generalization. Fuel LHV and HHV LHV Methane (CH4) Propane (C3H8) Isooctane (C8H18) Cetane (C16H34) Methanol (CH40) Ethanol (C2H60) Carbon Monoxide (CO) (MJ/kg) 50.0 46.4 44.2 44.0 20.0 26.9 10.1 HHV (MJ/kg) 55.5 50.4 47.8 47.3 22.7 29.7 10.1A hydrocarbon fuel has the following composition of dry products of combustion by volume: 12% CO2, 0.5% CO, 4% O2, and the rest N2. Determine the air-fuel ratio. Select one: a. 19.5 b. 17.5 c. 12.5 d. 15.5
- 5. A test run using this coal showed a dry products of combustion analysis by volume of nitrogen equals 82.5%, molecular weight of 30 kg flue gas per mol dry flue gas, and the weight of this dry flue gas is 15.03 kg per kg of coal. The actual ash-pit sample was 0.15 kg per kg of coal, of which 20% was carbon. What is the percentage excess air supplied to the fuel combustion in percent?The following gravimetric analysis on an ash and moisture free basis of a kilogram of Fuel oil are the following: C=87%; H=12%; N=2%, S=2%; and O=6%. The yields on the burning of the same fuel are in the following Orsat Analysis: C02=11%; CO=2%; 02=4.5%; and N2=82.5%. 1) Calculate the mass of dry flue gas in kilogram.2) Determine the mass of the ideal air in kilogram of air. 3) Determine the percent of excess air.4.1 fuel-rich air-fuel the exhaust gives the following 14.957; Cullg = 0.75% 0% H₂ = 0% 0₂ = 0%, with the rest being N₂. Write the balance chemical equation for one mole of this fuel at these conditions. CO = 1 Calculate : CHHS is burned in an engine with a ratio. Dry analysis of volume percents CO₂ : a- Air-fuel ratio. b. Equivalence ratio.