Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- Question 6 of 6 Points possible: 1.00 Not yet answered Consider the generic weak acid HA, for which Ka = 1.2 x 10. Which of the following mixtures would result in a buffer solution when 30.0 mL of each of the two solutions are mixed? Select one: 0.10 M NaOH and 0.10 M HA 0.20 M NaOH and 0.10 M HA 0.10 M NaOH and 0.20 M HA 0.01 M NaOH and 0.20 M HA None of the above are correctarrow_forwardWhen 30 .00 mL of 0.1011 M HCl in 50 mL of deionized water is titrated against 0.09889 M NaOH, the pH increases. What is the volume (in mL) of NaOH required to reach the equivalence point and a pH of 7.00? Find the pH when the volume of NaOH added is 0.02 mL less than the volume required to reach the equivalence point. Find the pH when the volume of NaOH added is 0.01 mL less than the volume required to reach the equivalence point. Find the pH when the volume of NaOH added is 0.02 mL more than the volume required to reach the equivalence point. Comment on the significance of the changes in pH values in relation to the increments of sodium hydroxide added when going “through” the end point. Define equivalence point. For a weak base/strong acid titration, is the pH at the equivalence point <, >, or equal to 7?arrow_forwardQUESTION 11 Which of the following acid/base conjugate pairs could you use to make a buffer solution with a pH of 12.55? The K, for the acids are given in parentheses. O Chlorous acid/ chlorite (K, = 1.1 x 10-2) O Ammonium / ammonia (K, = 5.8 x 10-10) O Benzoic acid / benzoate (K, = 6.3 x 10-5) O Hydrofluoric acid / fluoride (Kg = 6.6 x 10-4) O Hydrogen phosphate /phosphate (K, = 4.2 x 10-13)arrow_forward
- Questions 5-10 refer to the same weak acid/strong base (WA/SB) titration. The K₂ of hypobromous acid is 2.8 x 10-⁹.5 A 30.00 mL solution of 0.300 M hypobromous acid (HBrO) is being titrated with a solution that is 0.600 M in lithium hydroxide (LiOH). What is the solution pH when 25.00 mL of LiOH have been added? (Two decimal places) Type your answer...arrow_forwardCalculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. First what is the initial pH (before any NaOH is added)?The Ka for HOCl is 3.0 x 10-8 M. (the answer is 3.96) Please I really need these questions below answered they have to do with the above question. What is the pH after 6.40 mL of NaOH are added? What is the pH at the equivalence point? What is the pH after 11.00 mL of NaOH are added? What is the pH after 14.10 mL of NaOH are added? What is the pH when half the acid has been neutralized?arrow_forwardNumber 13arrow_forward
- 2. In the second titration, the molar mass of an unknown monoprotic acid is calculated. If 0.100 grams of unknown solid are dissolved in water and titrated with 4.68 mL of the NaOH, what is the molar mass of the solid? HINTS: Molar mass is grams / moles. We have grams from the weighed mass, we can calculate moles of acid from the titration. Monoprotic means that it produces 1 H+ per molecule. This means that our moles of NaOH added and moles of acid are the same. You will need to use your concentration of NaOH from the previous question Which is 0.1186arrow_forwardHi, im writting a practice titration lab. The purpose lab is to determine the concentration and Ka of a weak monoprotic acid (HA). You will also determine the identity of the acid. HA(aq) + NaOH(aq) → H2O(l) + NaA(aq) My question is:What volume of NaOH (titrant) was required to reach the equivalence point according to te table.arrow_forwardQuestion 4 a) Determine the pH of 0.10 M NAOH solution. b) Find out the pH of a 0.002 M acetic acid solution if it is 2.3% ionised at this dilution. c) A chemistry student desires to prepare one litre of a solution buffered at pH 9.00. How many grams of ammonium chloride haye to be added to one litre of 0.20 M NH3 to makesuch a buffer. pKb value of ammonia is 4.75 in the equation. NH3 + H20 = NH + OHarrow_forward
- Calculate the standard potential, Eº, for this reaction from its equilibrium constant at 298 K. X(s) + Y²+ (aq) — X²+ (aq) + Y(s) K = 4.57 × 10-³ TOOLS E = X10 Varrow_forwardQuestion 11 Question 12arrow_forwardAnswer Questions #27 through #31 about the titration curves below (labeled a and b) for two different bases. The titrant acid used in both cases was 0.100 M HCl and the volume of the base solutions in both cases was 75.0 mL mL. 14 14 12 12 - 10- 10 8- 6. 4. 2- 2- 20 40 60 80 100 20 40 60 80 100 Volume of acid added (mL) (a) (b) Volume of acid added (mL) 2014 Pearson Education Inc P Type here to search 11:17 AM (? 3/18/2021 -> ort sc 80 6. ece num ER/TY || на 0 04 2C Hdarrow_forward
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