Question 5 (1 point) Equimolar quantities of potassium fluoride and hydrofluoric acid are placed into solution. The equilibrium established is as follows: HF(aq) + H2O(l) | <--> F˜(aq) + H¸O*(aq) What happens to the above equilibrium if some acetic acid is added to the solution? Acetic acid ionizes so pH significantly increases. Acetic acid isn't in the equilbrium equation so it will have no effect on the pH of the solution. The acetic acid creates more hydronium ion so the equlibrium shifts left and pH is not changed significantly. The acetic acid creates more hydronium ion so the reaction shifts right and pH is not changed significantly.

Write the equilibrium expression for the following reaction. HF (aq) -> H+ (aq) + F- (aq)

The completed equilibrium table for a 0.270 M solution of propanoic acid is shown. HC,H;O,(aq) C,H,0, (aq) H*(aq) + initial 0.270 change +x +x -x equilibrium 0.270 – x What is the concentration of H† in the solution? [H*] = M Calculate the pH of the solution. pH =

Question 5 (1 point) Equimolar quantities of potassium fluoride and hydrofluoric acid are placed into solution. The equilibrium established is as follows: HF(aq) + H2O(l) F¯(aq) + H30+(aq) What happens to the above equilibrium if some acetic acid is added to the solution? Acetic acid ionizes so pH significantly increases. Acetic acid isn't in the equilbrium equation so it will have no effect on the pH of the solution. The acetic acid creates more hydronium ion so the equlibrium shifts left and pH is not changed significantly. The acetic acid creates more hydronium ion so the reaction shifts right and pH is not changed significantly.