Question 4. The New York Times reported that in America, 40% of firstmarriages end in divorce. Assuming that the trials are independent, find theprobability that in a random sample of 5 first marriages, at most one endsin divorce.(a) 0.259(b) 0.337(c) 0.663(d) 0.741Question 5. Calculate the probability that z is between -1.20 and 1.85 fora standard normal distribution. That is, find P(-1.20 < z < 1.85).(a) 0.1151(b) 0.8527(c) 0.8849(d) 0.9678Question 6. A survey to determine the number of pets one owns will collectwhich type of data?(a) qualitative(b))discreteatementa(c) bivariate(d) continuous

As per our guidelines we are suppose to answer only one question. Given,n=5p=0.40A random variable…

Answered: Question 4. The New York Times reported…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that for Americans in the age group 18-24 years, sixty-eight percent had private health insurance. In the age group 25-34 years, the percentage is seventy-five. If we select a random sample of 273 Americans from the 18-24 age group and an independent random sample of 247 Americans from the age group 25-34, then the probability that the difference in percent of private health insurances is between -6% and 6% between the two groups is approximately: d. 0.6005 c. 0 a. 0.3995 b. 0.0019 e. 0.419
The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population proportion is p = .17 and a simple random sample of 800 households will be selected from the population. What is the random variable in this narrative?
3. A recent article in the Journal of Urban Chicken Farmers reported the fraction of chickens that experience severe, moderate, or minor side effects from a new diet are 0.07, 0.15, and 0.78, respectively. Assuming that chickens respond independently, if 18 chickens were tested on the new diet, what is the Probability that 2, 4, and 12 chickens will suffer severe, moderate, or minor side effects, respectively? Probability that no chickens will suffer severe side effects? Mean number of chickens that will suffer severe side effects? Variance in the number of chickens that will suffer severe side effects? Conditional mean of the number of chickens that suffer severe side effects given that 17 suffer minor side effects. a. b. C. d. e.
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ll 36 l 12% 7 15:04 4G .. Question One: (a) If 4 balanced coins are tossed simultaneously (or 1 balanced coin is tossed 4 times), compute the entire probability distribution and plot it. (b) Compute and plot the probability distribution for a sample of 5 items taken at random from a production process known to produce 30% defective items.
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Question 4. The New York Times reported that in America, 40% of first marriages end in divorce. Assuming that the trials are independent, find the probability that in a random sample of 5 first marriages, at most one ends in divorce. (a) 0.259 (b) 0.337 (c) 0.663 (d) 0.741