Question 4 Draw Zaitsev and Hofmann products that are expected when each of the following compounds is treated with a strong base to give an E2 ELIMINATION product. Hint: Some compounds cannot produce both elimination products because they do not have two beta-hydrogen atoms: in these cases only ONE product will be possible. In cases when neither elimination products are possible, there will be NO REACTION. ? NO products are possible A B (NO REACTION) A B C D Zaitsev 1 Zaitsev 2 Zaitsev Hofmann only ONE product is possible

Calculate the concentration of unknown red dye solution

Based on the data, calculate the concentration of analyte in the ORIGINAL sample in ppm. Report to 1 decimal place Sample: A 10.00 mL aliquot of the unknown was placed in a 100.0 mL volumetric flask and made up to the mark will distilled water. The absorbance of this solution is 0.185. Sample + Spike: A 10.00 mL aliquot of the unknown and a 13.00 mL aliquot of the 46.00 ppm stock were both placed in the same 100.0 mL volumetric flask and diluted to the mark with water. The absorbance of this solution is 0.326.   ( Please type answer note write by hend)

The concentration of hydronium ions and hydroxide ions can vary widely in a solution, easily from 1 M to 1 x 10-14 M. This variation is too wide to fit on an analog readout. In order to make this into a smaller scale suitable for an analog readout, the log to the base 10 was used so that the read out is focused on powers of 10. Note that the log [1] = 0, and the log of 1 x 10-14 = -14. It was then decided that the numbers should be positive so the sign was changed. The way to measure concentrations of both H+ and OH- was thus defined as -log. This was then referred to as p. Thus, pH = -log[H+], pOH = -log[OH-], and pK = -log[Keq]. You need to figure out how to do this mathematical manipulation on your calculator. The acid-base reaction in pure water is H2O + H2O ⇔ H3O+1 + OH-1 and it was found that in pure water under standard conditions the [H3O+1] = [OH-1] = 1 x 10-7 M Neutral pH is defined as having a [H+] or [H3O+1] of 1 x 10-7 M. The pH of a neutral solution is thus pH = -log[1 x…