Question 4 A pulley is driven by a flat belt, the angle of lap being 120°. The belt is 100 mm wide by 6 mm thick and density is 1000 kg/m. If the coefficient of friction is 0.3 and the maximum stress in the belt is not to exceed 1.5 MPa. Calculate: the speed of the belt in m/s using the information related to driving pulley. the centrifugal tension and the tension on the first tight side of the belt T1. the greatest power the belt can transmit. 4.1. 4.2. 4.3

The height of the g point is 0.5m, the distance of the rear wheel to theg point is 1.75m, the distance of the front wheel to the g point is 1.8 m, and the car with a mass of 2100kg brakes suddenly while moving at 24v speed. l-Find the friction coefficient between the wheel and the road? 2-Find the way the vehicle takes until it stops?

Work-energy principle A 10 lb package moves down a conveyor belt and transition to a ramp. The angle of both the conveyor belt and the ramp = 12 degrees. (The length of the ramp = 10 ft (This is different than in the figure). The coefficient of kinetic (sliding) friction is mu_k = 0.40. Compute the work done by the friction as it slides on the ramp. Compute the height difference from the top to the bottom of the ramp. Compute the gravitational potential energy at the top relative to the bottom. The velocity at the end of the ramp = 2 ft/s. Compute the kinetic energy at the bottom. Use the work-energy principal to compute the kinetic energy at the top of the beginning of the ramp. Then, compute what the velocity at the top must have been.

While a vehicle with a mass of 2350 kg is moving at 120 km/h, suddenly braking It stops with an acceleration of -9.18 m/s2. There are two brake pads on each wheel of the vehicle. The friction coefficient between the brake pad and the brake disc is 0.3. During braking, assume 20 N/mm2 is the pressure on the brakke pad, find the area of the pad. Safety coefficient will be taken as 3