Question 30 Assume that EBX and ECX have the following values EBX: FF FF FF 75 ECX: 00 00 01 A2 After the execution of the instruction INC  EBX, ECX The Value in EBX is _________ Group of answer choices FFFFFF76 FFFFFF75 000001A2 none of them        Question 31   The Hexadecimal Representation for each of the following Binary number   11101111 Group of answer choices 239 EF FE none of them        Question 32   Assume that EBX and ECX have the following values EBX: FF FF FF 75 ECX: 00 00 01 A2 After the execution of the instruction MOV EBX, ECX The Value in EBX is _________ Group of answer choices 00000117 FFFFFF75 000001A2 none of them

Below is a list of 64-bit memory address references given as word address. Ox03, Oxb4, Ox2b, Ox01, Oxb7, Ox58, Oxbe, Ox02, Oxb5, Ox2e, Oxb6, Ox5b 0000 4 0100 8 1000 1100 1 0001 5 0101 9 1001 d 1101 2 0010 6 0110 a 1010 e 1110 3 0011 7 0111 b 1011 f 1111 Given a direct-mapped cache with 16 word blocks, what is the hit ratio? O 0.5 O 1 O 0.75 O 0.25

I 1:If the hexadecimal value 0xF0A2 is a two’s complement, halfword value, what would it be in base ten. A.28,836 B.61,602 C.-28,836 D.-3,934 E.3,934       2:Choose the best statement describing the difference between the instruction is 32 bits wide and the instruction can process a 32-bit data. A.   The instruction can process a 32-bit data means the instruction can do operation for many types of data bit length.   B.   The instruction is 32 bits wide means it can manipulate 32-bit data only.   C.   No different between both statements.   D.   The instruction is 32 bits wide means two memory locations are needed to store the instruction.   E.   The instruction is 32 bits wide means the instructions when it is converted to machine code, its length (size) is 32 bits.

4. mov bl, 10000000b movzx ax,bl after executing the above instructions ax will contain O 00000000 10000000 O 11111111 10000000 K

An 8-bit CPU adds the following two numbers. Determine the 8-bit sum (in hexadecimal) and the values of the zero (Z), sign (N), carry (C), and overflow (V) flags. 0x31 + 0x5F Sum= Z= N =_______ C =_______V=_