QUESTION 3 Researchers studying the effect of a dietary drug used a sample of 86 patients and found a 95% confidence interval for the mean weight loss, in pounds, to be (2.3, 5.6). If the researchers had used a sample of 50 patients instead of 86 patients, their confidence interval would have been: O wider O narrower O no way to tell

QUESTION 3 Researchers studying the effect of a dietary drug used a sample of 86 patients and found a 95% confidence interval for the mean weight loss, in pounds, to be (2.3, 5.6). If the researchers had used a sample of 50 patients instead of 86 patients, their confidence interval would have been: O wider O narrower O no way to tell

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 3 A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the cable can hold. The weight limit will be reported on cable packaging. The engineers take a random sample of 41 cables and apply weights to each of them until they break. The 41 cables have a mean breaking weight of 772.3 lb. The standard deviation of the breaking weight for the sample is 15.3 lb. Find the 95% confidence interval to estimate the mean breaking weight for this type cable. ( ) Your answer should be to 2 decimal places.
Question 5 A common claim is that garlic lowers cholesterol levels. In a test of the effectiveness of garlic, 45 subjects were treated with doses of raw garlic, and their cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/mL) have a mean of 4.94 mg/mL and a standard deviation of 18.51 mg/mL. Construct a 95% confidence interval for the average net change in LDL cholesterol after the garlic treatment. i. Procedure: Select an answer Select an answer One proportion Z procedure One mean T procedure One mean Z procedure One variance x² procedure ii. Assumptions: (select everything that applies) Simple random sample Sample size is greater than 30 Population standard deviation is unknown Population standard deviation is known The number of positive and negative responses ar Normal population iii. Unknown parameter: Select an answer Select an answer u, population mean o², population variance p, population proportion
QUESTION 5 The health department is estimating the percentage of smokers among adults aged between 18-22. A random sample of 50 students was used and 16 are reported as smokers. Find the corresponding critical value for calculating 97.5% confidence interval. Round your answer to three decimal places.
Question 9: compute a 95% confidence interval for the average blood pressure range of any individual that will take the blood pressure medication.
Question 1: You measure 29 randomly selected textbooks' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 7.5 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight.Give your answers as decimals, to two places
Question 7: can we use this to determine a 95% confidence interval for the average study time of All students for final exams?
Question 5 For a confidence level of 95%, find the critical value
QUESTION 24 A journal article reports that a random sample of 25 antivirus software packages was used as a basis for calculating a 98% t-based confidence interval for the true mean annual cost of an antivirus software in UAE. The resulting interval was (AED 191, AED 290). Find the margin of error (E) of the 98% t-based confidence interval. If needed, round your answer to one decimal place.
QUESTION 17 Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. A researcher was interested in comparing the resting pulse rates of people who exercise regularly and the pulse rates of people who do not exercise regularly. She obtained independent simple random samples of 16 people who do not exercise regularly and 12 people who do exercise regularly. The resting pulse rates (in beats per minute) were recorded and the summary statistics are as follows. Do not exercise regularly Exercise regularly x1 = 723 beats/min x2 = 68.1 beats/min %3D s1 = 10.9 beats/min s2 = 8.2 beats/min ni = 16 n2 = 12 Construct a 95% confidence interval for mu1 - mu2, the difference between the mean pulse rate of people who do not exercise regularly and the mean pulse rate of people who…
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QUESTION 1 Find the confidence level related to the critical value z 88% 12% 93% 94% Za/2=1.555 QUESTION 2 A research study reported a 95% confidence interval for the mean time of hip surgeries based on a sample of 91 patients as (116 minutes, 138 minutes). Which of the following statements is correct about the given interval? A. Incorrect B. Correct ✓ The mean time of hip surgeries of the 91 patients in the selected sample falls between 116 and 138 minutes. ✓ The mean time of hip surgeries of any sample of 91 patients will fall between 116 and 138 minutes. 95% of hip surgeries take between 116 and 138 minutes. We are 95% confident that the mean time of hip surgeries will be between 116 and 138 minutes. QUESTION 3 A survey of 64 popular restaurants is used to estimate the mean number of kitchen employees. Assume that the number of kitchen employees is right-skewed, which distribution should be used to construct the confidence interval? Neither standard normal distribution nor t…