Question 3 A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the metal in a graduated cylinder filled with 20.00 mL of water. The metal increased the volume of water to 22.90 mL. Calculate the density of the metal and determine the identity of the metal using the table below. Density (g/mL) Metal Lead Silver 11.3 10.5

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### Question 3

A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the metal in a graduated cylinder filled with 20.00 mL of water. The metal increased the volume of water to 22.90 mL. Calculate the density of the metal and determine the identity of the metal using the table below.


| **Metal** | **Density (g/mL)** |
|-----------|---------------------|
| Lead      | 11.3                |
| Silver    | 10.5                |


#### Explanation:

To determine the density of the unknown metal, use the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

1. **Calculate the volume of the metal:**

   The metal increased the volume of water from 20.00 mL to 22.90 mL. Therefore, the volume of the metal is:

   \[ \text{Volume of the metal} = 22.90 \, \text{mL} - 20.00 \, \text{mL} = 2.90 \, \text{mL} \]

2. **Calculate the density of the metal:**
   
   \[ \text{Density} = \frac{30.2 \, \text{g}}{2.90 \, \text{mL}} = 10.41 \, \text{g/mL} \]

3. **Determine the identity of the metal:**

   Compare the calculated density to the densities provided in the table:

   - Lead: 11.3 g/mL
   - Silver: 10.5 g/mL

   The calculated density of 10.41 g/mL is closer to the density of Silver (10.5 g/mL). Therefore, the unknown metal is likely Silver.
Transcribed Image Text:### Question 3 A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the metal in a graduated cylinder filled with 20.00 mL of water. The metal increased the volume of water to 22.90 mL. Calculate the density of the metal and determine the identity of the metal using the table below. | **Metal** | **Density (g/mL)** | |-----------|---------------------| | Lead | 11.3 | | Silver | 10.5 | #### Explanation: To determine the density of the unknown metal, use the formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] 1. **Calculate the volume of the metal:** The metal increased the volume of water from 20.00 mL to 22.90 mL. Therefore, the volume of the metal is: \[ \text{Volume of the metal} = 22.90 \, \text{mL} - 20.00 \, \text{mL} = 2.90 \, \text{mL} \] 2. **Calculate the density of the metal:** \[ \text{Density} = \frac{30.2 \, \text{g}}{2.90 \, \text{mL}} = 10.41 \, \text{g/mL} \] 3. **Determine the identity of the metal:** Compare the calculated density to the densities provided in the table: - Lead: 11.3 g/mL - Silver: 10.5 g/mL The calculated density of 10.41 g/mL is closer to the density of Silver (10.5 g/mL). Therefore, the unknown metal is likely Silver.
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