QUESTION 24 To estimate the average time it takes to assemble a certain computer component, the industrial engineer at an electronics firm timed 25 technicians in the performance of this task, getting a mean of 12.5 minutes anda standard deviation of 2 minutes. Construct a 98% confidence interval of the actual average time required to do the job assuming that the actual time follows a normal distribution. O (11.678, 13.322) O (11.570, 13.430) O (11.503, 13.497) O (11.631, 13.369)

QUESTION 24 To estimate the average time it takes to assemble a certain computer component, the industrial engineer at an electronics firm timed 25 technicians in the performance of this task, getting a mean of 12.5 minutes anda standard deviation of 2 minutes. Construct a 98% confidence interval of the actual average time required to do the job assuming that the actual time follows a normal distribution. O (11.678, 13.322) O (11.570, 13.430) O (11.503, 13.497) O (11.631, 13.369)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Suppose that for the past several decades, daily precipitation in Seattle, Washington has had a mean of 2.4 mm and a standard deviation of 11.4 mm. Researchers suspect that in recent years, the mean amount of daily precipitation has changed, so they plan to obtain data for a random sample of 195 days over the past five years and use this data to conduct a one-sample ?z‑test of ?0:?=2.4H0:μ=2.4 mm against ?1:?≠2.4H1:μ≠2.4 mm, where ?μ is the mean daily precipitation for the last five years. Although they realize that rainfall does not follow a normal distribution, they feel safe using a ?z‑test because the sample size is large. The researchers want to know what the power of this test is to reject the null hypothesis at significance level ?=0.05α=0.05 if the actual mean daily precipitation is 2.6 mm or more. Computing power by hand requires two steps. The first step is to use a significance level of 0.05 to determine the values of the sample mean for which they will reject their null…
In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1197 and the standard deviation was 166.9. Further research suggests that the population mean score on this test for high school seniors is 1018. Does the t-value for the original sample fall between -to.95 and to.95? Assume that the population of test scores for high school seniors is normally distributed. fall between -to.95 and to.95 because to.95 = The t-value of t= (Round to two decimal places as needed.) C
A population has a mean of 200 and a standard deviation of 90. Suppose a simple random sample of size 125 is selected and is used to estimate μ. Use z-table. a. What is the probability that the sample mean will be within 18 of the population mean (to 4 decimals)? b. What is the probability that the sample mean will be within 16 of the population mean (to 4 decimals)?
From a sample with n=40, the mean duration of a geyser's eruptions is 3.13 minutes and the standard deviation is 0.82 minutes. Using Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.49 and 4.77 minutes.
A researcher is interested in estimating the mean time it takes adults to learn a certain task. He wants to be 99% confident that the mean time for a sample of adults is within 0.6 minutes of μ. In a small pilot study, the standard deviation of learning times was 6.9 minutes. How large a sample of adults should be tested?
The ages of a group of 149 randomly selected adult females have a standard deviation of 16.5 years. Assume that the ages of female statistics students have less variation than ages of females in the general population, so let σ=16.5 years for the sample size calculation. How many female statistics student ages must be obtained in order to estimate the mean age of all female statisticsstudents? Assume that we want 90% confidence that the sample mean is within one-half year of the population mean. Does it seem reasonable to assume that the ages of female statistics students have less variation than ages of females in the general population? Question content area bottom Part 1 The required sample size is enter your response here.
Agricultural scientists are testing a new chicken feed to see whether it increases the number of eggs laid. The scientists divided a flock in half and gave half of the chickens the new feed, while the other half were given a regular feed. The eggs laid in a one-year period for a random sample of 10 chickens using the new feed and 10 chickens using the regular feed are recorded. Assume that the population standard deviation of number of eggs laid is 12 eggs per year for both groups and that the number of eggs laid per year is normally distributed. Let the chickens given the new feed be the first sample, and let the chickens given the regular feed be the second sample. The scientists conduct a two-mean hypothesis test at the 0.05 level of significance to test if there is evidence that the new feed increases the number of eggs laid. (a) Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ1=μ2;…
The ages of a group of 132 randomly selected adult females have a standard deviation of 16.1 years. Assume that the ages of female statistics students have less variation than ages of females in the general population, so let σ=16.1 years for the sample size calculation. How many female statistics student ages must be obtained in order to estimate the mean age of all female statistics students? Assume that we want 95% confidence that the sample mean is within one-half year of the population mean. Does it seem reasonable to assume that the ages of female statistics students have less variation than ages of females in the general population?The required sample size is
In a random sample of 8 cell phones, the mean full retail price was $549.30 and the standard deviation was $182.00. Further research suggests that the population mean is $425.14. Does the t-value for the original sample fall between - to 95 and to 95? Assume that the population of full retail prices for cell phones is normally distributed. The t-value of t = fall between - to 95 and to 95 because to 95 (Round to two decima d.) does not does
From a sample with n = 32, the mean duration of a geyser's eruptions is 3.42 minutes and the standard deviation is 1.12 minutes. Using Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.18 and 5.66 minutes. At least of the eruptions lasted between 1.18 and 5.66 minutes. (Simplify your answer.)
Q3: The effective life of a component used in a jet-turbine aircraft engine is a random variable with mean 5000 hours and standard deviation 40 hours. The distribution of effective life is fairly close to a normal component that increases the mean life to 5030 hours and decreases the standard deviation to 30 hours. distribution. The engine manufacturer introduces an improvement into the manufacturing process for this Suppose that a random sample of n₁ = 16 components is selected from the "Old" process and a random sample of n₂ = 25 components is selected from the "Improved" process. What is the probability that difference in the two-sample means that the old and improved processes can be regarded as independent populations. 5 X₂X₁ is at least 15 hours? Assume
suppose that for a sexually active male drosophila fruit fly in a particular genetics lab the population mean lifespan is 38.9 days with a population standard deviation of 12.0 days when she experimentally removed all females from a simple random sample of 24 this drosophila flies in her lab a researcher in the slab found that 24 sexually inactive males had a mean lifespan of 62.5 days with a standard deviation of 14.1 days answer the questions below about the experiment and about testing weather sexual activity affects how long males Drosophila live. How do you find the Critical Value? How do you find theP-Value? reject or fail to reject the null hypothesis?