Question 2 Find dy at x=0 for each part below. dx x sec (ax+) a) (here the answer should be in terms of g and b, assume that bz - 2). y= b+ax+2

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A: To determine the value of integral.

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A: formulas we use: ddxf+g=dfdx+dgdxddxkx=k; k is a constant.dkdx=0; k is constant.ddx(x)=1.

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A: LetI=∫212dxWe know that ∫abfxdx=-∫bafxdx, a<bThereforeI=-∫122dxTake constant outI=-2∫12dxWe know…

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Q: If-xy - 3+x=0 then find dy at the dx² point (-1, 4) in simplest form.

A: See the details solution in below

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A: On solving this integration we will get

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A: Since you have asked multiple question,as per our guidelines we are supposed to answer only one…

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A: Given query is to find the value of integral.

Q: dy as a function of x. Write the function in the form y = f(u) and u= g(x). Then find y = (- 2x +8)…

A: We know that ,  if y = f ( u ) and u = g ( x )  Then  dy / dx = f ' ( u ) • g ' ( x )

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A: We need to evaluate the given integration for which we will use substitution method.

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A: The given problem is related to complex analysis. First we consider the integrand function as f(z)…

Q: Change (x + 9)? + y? = 169 to x? + y? + Dx + Ey + F = 0. Change x? + y? – 8x – 8y + 16 = 0 to (x-h)?…

A: topic - equation of circles

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A: This problem can be solved using the concept of integration by substitution.

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A: Solving the given integral by substitution.

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A: Consider the provided integral, ∫x24-x6dx Solve the above integral and write down the answer in term…

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A: We need to find the first order and 2nd order derivatives of the given functions.

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A: We have to compute the following integral: . We will use the substitution method to evaluate the…

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.