Question 15. An object is launched on the moon at 16 feet per second (f/s) from a 1152-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-16t^2+16t+1152, where s is in feet. When does the object strike the moon's surface and why?

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Question 15. An object is launched on the moon at 16 feet per second (f/s) from a
1152-foot tall tower. The equation for the object's height s at time t seconds after
launch is s(t)=-16t^2+16t+1152, where s is in feet. When does the object strike the
moon's surface and why?
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Transcribed Image Text:Your answer Question 15. An object is launched on the moon at 16 feet per second (f/s) from a 1152-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-16t^2+16t+1152, where s is in feet. When does the object strike the moon's surface and why? Your answer Вack Submit Never submit passwords through Google Forms. This form was created inside of East Orange School District. Report Abuse Google Forms OCT
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