QUESTION 11 For the exothermic reaction below, Kc = 70 at 425 °C. At T = 202 °C, the AG° = -19802 J/mol. Use K = exp(-AG/RT] to show that the value of the equilibrium constant Kc will, H2(9) +12(9) < 2(g) O a. not change when the temperature is changed to 202 °C. O b.decrease to Ke ~35 when the temperature is changed to 202 °C. Oc. increase to Kc ~150 when the temperature is changed to 202 °C. O d.decrease to Kc ~0.006 because it affects the catalyst at T = 202 °C. O e. remain at Kc ~70 because the volume decreases at T = 202 °C.

please help solve Concentration of AR Stock Solution (ppmppm) 21.22   Unrounded Rounded Concentration of AR Stock Solution (μMμM) 42.7461 42.7

Question: Identify products A and B giving evidence from the student's observations and the data provided. *ive sent a picture

SELECT correct responses only 1) Volume percent (v/v%) is temperature-independent. 2) There are three major approaches to expressing solution concentration in terms of percent concentration: weight percent, volume percent, and weight/volume percent. 3) Weight/volume percent (w/v%) is a unit-less quantity. 4) The term 'percent' refers to 'parts per thousand'. 5)A standard solution is a reagent of known concentration that is used to carry out a volumetric titration. 6) The endpoint of a titration is the theoretical point reached when the amount of added titrant is chemically equivalent to the amount of analyte in a sample. 7) A substance that changes color in response to chemical equivalence is known as an indicator. 8) Given a sufficiently diligent and experienced experimenter, it is sometimes possible to reach a titration volume error value of 0.