QUESTION 10 The element boron has twa naturally occuming isotopes with masses of 10.0129 amu and 11.0093 amu What would be the fractional abundance of the first isotope fthe atomic weight was 103318 amu eCanceet The mass en the periodic table of each element aa weighted average of the mass from all of the isotopes and s determined by AM obsfAM+fAM 2 where fis the fractional abundance of a gven isotope. The abundance of sotope 1 is 100f-Also note that the sum of the fractional abundances equals one ie.f+2.

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QUESTION 10
The element boron has twa naturally occurring isotopes with masses of 10.0129 amu and 11.0093 amu. What would be the fractional abundance of the first isotope. if the atomic weight was
10.3318 amu?
Key Concept The mass on the periodic table of each element is a weighted average of the mass from all of the isotopes and is determined by: AM obs fAM+f2AM 2 where fis the
fractional abundance of a given isotope. The abundance of isotope 1 is 100f 1.Also note that the sum of the fractional abundances equals one i.e. f1+121.
Transcribed Image Text:QUESTION 10 The element boron has twa naturally occurring isotopes with masses of 10.0129 amu and 11.0093 amu. What would be the fractional abundance of the first isotope. if the atomic weight was 10.3318 amu? Key Concept The mass on the periodic table of each element is a weighted average of the mass from all of the isotopes and is determined by: AM obs fAM+f2AM 2 where fis the fractional abundance of a given isotope. The abundance of isotope 1 is 100f 1.Also note that the sum of the fractional abundances equals one i.e. f1+121.
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