Question 1. The impedance of a 150 km long transmission line is z = 0.06+ j0.48 2/km, and the shunt admittance value is given as y=j3.33x10-6 S/km. Under 250 kV voltage at the end of the line A power of 250 MW is drawn with a reverse power factor cos p = 0.95. Nominal л equivalent using the circuit; a) Find the ABCD parameters. b) Find the voltage, current and power factor per line. (Ctrl) Y

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
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Question 1. The impedance of a 150 km long transmission line is ? = 0.06 + ?0.48 ?/??, and the shunt admittance value is given as ? = ?3.33?10−6 ?/??. Under 250 kV voltage at the end of the line A power of 250 MW is drawn with a reverse power factor cos ? = 0.95. Nominal π equivalent using the circuit; a) Find the ABCD parameters. b) Find the voltage, current and power factor per line.

Question 1. The impedance of a 150 km long
transmission line is z = 0.06 + j0.48 2/km, and the
shunt
admittance value is given as y=j3.33x10-6 S/km.
Under 250 kV voltage at the end of the line
A power of 250 MW is drawn with a reverse power
factor cos p = 0.95. Nominal л equivalent
using the circuit;
a) Find the ABCD parameters.
b) Find the voltage, current and power factor per line.
(Ctrl) -
Transcribed Image Text:Question 1. The impedance of a 150 km long transmission line is z = 0.06 + j0.48 2/km, and the shunt admittance value is given as y=j3.33x10-6 S/km. Under 250 kV voltage at the end of the line A power of 250 MW is drawn with a reverse power factor cos p = 0.95. Nominal л equivalent using the circuit; a) Find the ABCD parameters. b) Find the voltage, current and power factor per line. (Ctrl) -
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