Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle

Elements Of Electromagnetics
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the value of figure is not 6+b/10.True value is 6+a/10.

a = 6

Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder
and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m,
the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter
of length. (y-9,81 KN/m³).
Pivot
6+ b/10 m
2+ a/10m
4R
3x
= = 0.05488R
I =-0.01647R
Hint: le) Quarter-circle
Transcribed Image Text:Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle
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