QUESTION 1 For the following reaction at 1000 K, 1.04 mol SO2 and 1.12 mol O₂ are placed into a 0.94 L flask. At equilibrium, 0.801 mol of SO3 has been formed. Calculate Kc. Report your answer to the tenths place. 2 SO2(g) + O2(g) = 2 SO3(9) 1.04 1.106 X 8.7 K₁= 0.94 [0.801]² [0.305][0.190] 112 S 01 50₂ 11.106 Ог 1.191 503 0 0.801 -D HDDS +0.801 C 0.801 0.801 x 1/2 50₂ = D.801x1020.4005 773
QUESTION 1 For the following reaction at 1000 K, 1.04 mol SO2 and 1.12 mol O₂ are placed into a 0.94 L flask. At equilibrium, 0.801 mol of SO3 has been formed. Calculate Kc. Report your answer to the tenths place. 2 SO2(g) + O2(g) = 2 SO3(9) 1.04 1.106 X 8.7 K₁= 0.94 [0.801]² [0.305][0.190] 112 S 01 50₂ 11.106 Ог 1.191 503 0 0.801 -D HDDS +0.801 C 0.801 0.801 x 1/2 50₂ = D.801x1020.4005 773
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter19: The Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 60QRT
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![QUESTION 1
For the following reaction at 1000 K, 1.04 mol SO2 and 1.12 mol O₂ are placed into a 0.94 L flask. At equilibrium, 0.801 mol of SO3 has been formed.
Calculate Kc. Report your answer to the tenths place.
2 SO2(g) + O2(g) 2 SO3(9)
1.04
[0.801]²
1.106
K₁=
X 8.7
0.94
[0.305][0.790]
14.7
1.12
0.94
=
= 1.191
503
0
502
0₂
1
1.106
1.191
C -0.801 -0.4005 +0.801
e 0.305 0.790 0.801
0.801
x 1/2 50₂ = 0.801
1020.4005
0.801 x
Kc= 8.73](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f844d00-6c5e-468b-9347-2d727432be7a%2F05acac5a-78b5-4243-90ce-77348c7aac01%2F3j3mmch_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 1
For the following reaction at 1000 K, 1.04 mol SO2 and 1.12 mol O₂ are placed into a 0.94 L flask. At equilibrium, 0.801 mol of SO3 has been formed.
Calculate Kc. Report your answer to the tenths place.
2 SO2(g) + O2(g) 2 SO3(9)
1.04
[0.801]²
1.106
K₁=
X 8.7
0.94
[0.305][0.790]
14.7
1.12
0.94
=
= 1.191
503
0
502
0₂
1
1.106
1.191
C -0.801 -0.4005 +0.801
e 0.305 0.790 0.801
0.801
x 1/2 50₂ = 0.801
1020.4005
0.801 x
Kc= 8.73
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