
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Please answer question and just send me the paper solutions asap dont type the answer question 13abcd and use this formula

Transcribed Image Text:ay quiz eq.png
hotos
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GMm
mearth = 5.97 x 1024kg
mmoon
7.34 x 1022kg
Tmoon = 1737 fA km
Nm2
G = 6.67x10-11
kg?
v2
a. = -
re = 6378 km
472r
ac = T2
a. = 4n2rf2
kq192
F.
mproton = 1.67 x 10-27kg
melectron = 9.11 x 10-31kg
F = qe
Nm2
k = 8.99x109
C2
delectron/proton = ±1.60x10-19C
AE, = -W = -F.Ad=-qeAd
ΔΕ,
AV =
AV
kq
E =
E =
Ad
Fmagnetic = qvBsin®
me = 9.11 10-31kg
q = ±1.60 10-19C
1
E, =
2
E = qAV
m, = 1.67 * 10-27kg
F. = qe
v2
a. =.
10:12 AM
DE
. 4) d ENG
2021-06-17

Transcribed Image Text:Question 13
A particle accelerator is used to accelerate particles... (obviously right?).
a) Draw a diagram that would represent a proton, starting from rest, and passing
between two plates with a potential difference of 5. 3 x 10° V, and the plates
separated 12cm apart. (Include SIGNS on plates), accelerating.
b) How fast would the proton be traveling as it goes from one side to the other?
c) What would be the magnitude of the electric field strength?
d) What would be the acceleration of the proton?
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