Ql-phase step down transformer 1250 KVA, 1 1000/2200 V, 50 Hz .The resistance /phase and leakage reactance phase of the primary winding are 0.78 2 and 4.82 and the corresponding values for the secondary winding are 0.012 and 0.002 respectively if the primary winding is connected in delta and secondary in star calculate: )The voltage to be applied at normal frequency to the primary to circulate full-load through it when the secondary is short-circuited Ii) The full load copper loss

Find the following : 1.Ripple Voltage (vpp) 2. Zero-to peak ripple(Vop) 3.secondary winding of the transformer high line and low line

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A short transmission line connects a step-up transformer on the source side with a series impedance of j0.5 ohms (referred to the primary) to a step-down transformer on the load side with a series impedance of 50 ohms (referred to the primary). The turn ratio of the step-up transformer is 1:14 and a no-load primary voltage of 17 (line-to-line) kV. The step- down transformer has a turn ratio of 18:1 and it has a Y-connected, balanced load of 0.463 +j 0.0772 ohms connected to its secondary side. A capacitor bank of -j0.324 ohms is added parallel to the load. Assuming an ideal transmission line, the effective impedance (per phase) of the system seen by the source would be: O A. 0.292 + j0.375 O B. None of the other choices are correct O C. 0.584 + j0.750 O D.0.196 + j0.158 O E. 5.84 + j7.5