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- A 3.1kg ball was dropped from an unknown heigh to the ground, find the work done by the gravity after 5 seconds. 2 s 3 s 4 s .5s ↑Consider the following physical situations. Identify the forces which do work upon the indicated object (in boldface type) and categorize them as conservative or non-conservative forces. Then indicate whether the total mechanical energy of the object changes; it it changes, then indicate whether the change is a positive or negative change. Finally, indicate whether the potential energy and the kinetic energy changes; if PE or KE changes, then indicate whether the change is a positive or negative change. Description of Physical Situation Identity of Forces Which Do Work: Change in TME Change in PE Change in KE Conserv. Non- Conserv. Yes (+ or -) No Yes (+ or -) No Yes (+ or -) No a. A force is applied to move a physics cart from the floor to the top of an inclined plane at a constant speed. _________ _________ _____ _____ _____ _____ _____ _____ b. A physics student scurries up a flight of stairs at constant speed. _________ _________ _____ _____ _____ _____ _____…Needed to be solved this question correctly in 20 minutes and get the thumbs up please show me neat and clean work for it by hand solution needed only
- Energy is always created in terms of law of conservation of energy. Show solution if applicable and need computation, then choose from the choices below: True Falseanswer is correct, need to see work pleaseWhich of the following force is doing a positive work on the box? The box is displaced to the right as shown. Select all apply.
- Kindly share detailed explanation for each step.Circular Motion A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point "A", and the total mechanical energy of the bead is assumed to be constant as it moves around the circle. Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to point "B" each cycle. 10 m/s 2 m 1 Note: vector directions should be given as the "standard" angle with 0 <0 < 360 degrees 30° Calculate the direction of the average velocity from point "A" to "B" (based on the 0.62 seconds mentioned in the description).. Enter the standard angle in degrees.