Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Q6//The farm shown in the figure is irrigated by furrow
system:
• FC=32% by vol. ,W P = 18% by vol.
. PAD= 70%
• Depth of root zone-100 cm
•
•
•
•
Spacing between furrows = 80 cm
The field is irrigated 2 days in week
Total available discharge Qa= 60 Lps
Discharge of one furrow.q=1.0 Lps
Neglect any service area, calculate:
a) length of one furrow and their total number
b) number of furrows irrigated at the same
time and number of irrigation groups
c) application time of any group
d) net irrigation depth
el application efficiency
0.1%
288m
↑
200m
+
0.5%

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Step 2: Calculating Length of one furrow and their total number.

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Step 3: Finding Number of furrows irrigated at the same time and number of irrigation groups

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Step 4: Finding Application time of any group.

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Step 5: Finding Net irrigation depth

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Step 6: Finding Application efficiency

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