Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Storm Sewers and Detention

The storm drains system transports rainwater or stormwater and other runoff from roads, parking lots, and roof downpipes directly to nearby creeks, rivers, or the sea without any treatment.

Question

Q6//The farm shown in the figure is irrigated by furrow
system:
• FC=32% by vol. ,W P = 18% by vol.
. PAD= 70%
• Depth of root zone-100 cm
•
•
•
•
Spacing between furrows = 80 cm
The field is irrigated 2 days in week
Total available discharge Qa= 60 Lps
Discharge of one furrow.q=1.0 Lps
Neglect any service area, calculate:
a) length of one furrow and their total number
b) number of furrows irrigated at the same
time and number of irrigation groups
c) application time of any group
d) net irrigation depth
el application efficiency
0.1%
288m
↑
200m
+
0.5%

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Step 2: Calculating Length of one furrow and their total number.

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Step 3: Finding Number of furrows irrigated at the same time and number of irrigation groups

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Step 4: Finding Application time of any group.

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Step 5: Finding Net irrigation depth

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Step 6: Finding Application efficiency

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A stream of 200 lps was diverted from the river and 150 lps were delivered to the field. An area of 3 hectares was irrigated in 8 hours. The root-zone depth was 1.8 m. The run-off averaged 50 lps for 3 hours. The depth of water penetration varied linearly from 1.8 m at a head of the field to 1.2 m at the end of the field. Determine the water-conveyance efficiency, the water-application efficiency, the water storage efficiency, and the water distribution efficiency.
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Q1: The water content at the field capacity is 27.2% by weight and it was 19% by weight for irrigation (wilting point), depth of the root zone is 0.92m and the apparent specific gravity is 1.3. Find: 1. The depth of water required to reach moisture in this soil to its field capacity. 2. The time required to irrigate 12 mishara in discharge equal to 75 €/s and 65% the efficiency of irrigation (Ea).
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I need the answer as soon as possible
Q#2 The moisture holding capacity of the soil in a 100-hectare farm is 18 cm/m, the field is to be irrigated when 50% of t'ne available moisture in the root zone is depleted. The irrigation water is to be supplied by a pump working for 10 hours a day, and water application efficiency is 75%. Details of crops planned for cultivation area are as follows: Root z'one depth (m) Peak rate of moisture use (mm/day) 5 4 Crop X Y Solve for 1) The capacity of irrigation system required, to irrigate crop X in 36 hectares. 2) The area of crop Y that can be irrigated when the available capacity of irrigation is 40 L/s. 1 0.8