Q6A
A study was conducted that measured the total brain volume (TBV) (in mm3) of patients that had schizophrenia and patients that are considered normal. Table #1 contains the TBV of the normal patients and Table #2 contains the TBV of schizophrenia patients ("SOCR data Oct2009," 2013).
Table #1: Total Brain Volume (in mm3) of Normal Patients
1663407 |
1583940 |
1299470 |
1535137 |
1431890 |
1578698 |
1453510 |
1650348 |
1288971 |
1366346 |
1326402 |
1503005 |
1474790 |
1317156 |
1441045 |
1463498 |
1650207 |
1523045 |
1441636 |
1432033 |
1420416 |
1480171 |
1360810 |
1410213 |
1574808 |
1502702 |
1203344 |
1319737 |
1688990 |
1292641 |
1512571 |
1635918 |
|
|
|
|
Table #2: Total Brain Volume (in mm3) of Schizophrenia Patients
1331777 |
1487886 |
1066075 |
1297327 |
1499983 |
1861991 |
1368378 |
1476891 |
1443775 |
1337827 |
1658258 |
1588132 |
1690182 |
1569413 |
1177002 |
1387893 |
1483763 |
1688950 |
1563593 |
1317885 |
1420249 |
1363859 |
1238979 |
1286638 |
1325525 |
1588573 |
1476254 |
1648209 |
1354054 |
1354649 |
1636119 |
|
|
|
|
|
Is there enough evidence to show that the patients with schizophrenia have less TBV on average than a patient that is considered normal? Test at the 10% level.
(i) Let μ1 =
A. μ1 + μ2 = 0
B. μ1 – μ2 < 0 (μ1 < μ2)
C. μ1 − μ2 > 0 (μ1 > μ2)
D. μ1 − μ2 = 0 (μ1 = μ2)
Enter letter corresponding to correct answer
(ii) Let μ1 = mean TBV of patients that are considered normal. Let μ2 = mean TBV of patients that had schizophrenia. Which of the following statements correctly defines the alternative hypothesis HA?
A. μ1 − μ2 = 0 (μ1 = μ2)
B. μ1 – μ2 < 0 (μ1 < μ2)
C. μ1 − μ2 > 0 (μ1 > μ2)
D. μ1 + μ2 = 0
Enter letter corresponding to correct answer
Enter in decimal form. Examples of correctly entered answers: 0.01 0.02 0.05 0.10
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