Q5. Construct a pushdown automaton (PDA) that recognizes the following language: Each string of the language contains at least two a's or four b's over the alphabet (a, b} Examples: ba (is not accepted, it doesn't contain at least two a's, also, it doesn't contain at least four b's) aba (is accepted, it contains at least two a's) babbb (is accepted, it contains at least four b's) bab (is not accepted, it doesn't contain at least two a's, also, it doesn't contain at least four b's)

Task 4: The InstantRide User Satisfaction team is a core team for InstantRide, and they focus on increasing the customer satisfaction. They want to learn the travel time for each ride in the system. You need to return the USER_ID, and the TRAVEL_TIME column which is calculated using the TIMEDIFF function on the TRAVEL_END_TIME and the TRAVEL_START_TIME.

bbhosted.cuny.edu/webapps/assessment/take/launch.jsp?course assessment_id=_1787700_1&course_ id3 1950256 1&content_id= 55349866 1&istep=Dnull ¥ Question Completion Status: Given a truth table below with the first two columns of truth values provided: b. f(p,a) 1 T 2 T 3 F 4 Which of the answers below contains the truth values for the third column when f(p,q) = (peq) →(q) ? Column 3 Column 3 truth values: Column 3 Column 3 truth values: Column 3 truth values truth truth values: values: 1 T 1 T 1 F 1 T None of the other 1 F O2 T O 2 F O answers provided is O 2 F 2 T correct. 2 T 3 F 3 T 3 F 3 T 3 F 4 T 4F 4 T 4 T 4 F Save All Answers Click Save and Submit to save and subnut. Chck Save All Answers to save all answers. Type here to search 6 66 F. F.

Every supper key is also a primary key True or false?

Hello I am receiving this error whenever I try to import it into MySQL using this code  SELECT store_id AS Store, COUNT(*) AS Num_CustomersFROM sakila.customerGROUP BY store_idORDER BY store_id DESC, COUNT(*) DESC;SELECT film.title AS Title, rental.rental_date AS Rental_Date, rental.return_date AS Return_DateFROM sakila.customerJOIN sakila.rental ON customer.customer_id = rental.customer_idJOIN sakila.inventory ON rental.inventory_id = inventory.inventory_idJOIN sakila.film ON inventory.film_id = film.film_idWHERE customer.first_name = 'JO' AND customer.last_name = 'FOWLER'ORDER BY rental.rental_date ASC;REPLACE VIEW top_rental_films ASCREATE OR SELECT film.title AS FilmTitle, COUNT(rental.rental_id) AS Num_Rentals, AVG(payment.amount) AS Avg_AmtFROM sakila.filmJOIN sakila.inventory ON film.film_id = inventory.film_idJOIN sakila.rental ON inventory.inventory_id = rental.inventory_idJOIN sakila.payment ON rental.rental_id = payment.rental_idGROUP BY film.film_idORDER BY…

write the code for the following triggers in MySQL following the style shown in the text. A: When adding a customer, add the customer balance multiplied by the sales rep's commission rate to the commission for the corresponding sales rep. B: When updating a customer, add the difference between the new balance and the old balance multiplied by the sales rep's commission rate to the commission for the corresponding sales rep. C: When deleting a customer, subtract the balance multiplied by the sales rep's commission rate from the commission for the corresponding sales rep.   CREATE TABLE REP(REP_NUM CHAR(2) PRIMARY KEY,LAST_NAME CHAR(15),FIRST_NAME CHAR(15),STREET CHAR(15),CITY CHAR(15),STATE CHAR(2),POSTAL_CODE CHAR(5),COMMISSION DECIMAL(7,2),RATE DECIMAL(3,2) );CREATE TABLE CUSTOMER(CUSTOMER_NUM CHAR(3) PRIMARY KEY,CUSTOMER_NAME CHAR(35) NOT NULL,STREET CHAR(20),CITY CHAR(15),STATE CHAR(2),POSTAL_CODE CHAR(5),BALANCE DECIMAL(8,2),CREDIT_LIMIT DECIMAL(8,2),REP_NUM CHAR(2) );INSERT INTO…

in PHP Make self join on store. finds all pair of stores that have the same manager_staff_id . Make inner join with staff. You must output store_id and full name of manager.

The InstantRide Driver Relationship team wants to learn how many travels each driver has done in the month of October. You need to send them the DRIVER_ID, and two calculated columns: DAY and RIDES. The DAY column is calculated using the DAY() function with the TRAVEL_START_TIME as the argument. The RIDES column is calculated by using the COUNT() function to determine the number of rides given for each day. Filter the results with the MONTH function.

Which result set requires a JOIN?     Showing all album titles with both artist ID and album ID Showing artist names with artist_id's Showing artist_id with album title Showing all album_id's with artist names

Sql server 2019 Get a count of Invoices that have a Payment Total greater than $1,000.