Q5: The following solution in blue is provided by ChatGPT for the following question. Please find out theerrors it made and show the step-by-step solution by yourself.Water in a vertical (i.e., gravitational force of the fluid in the nozzle plays a role, and the elevationchange in the Bernoulli's Equation, if needed, should be considered) pipe is charging from an attachedbend nozzle into the atmosphere as shown in Fig. 5. The nozzle's weight is 20 kg. The pipe and thenozzle are connected by a flange. The gage pressure of the flow at the flange is 35 kPa when thedischarge rate is 0.1 m³/s. The volume of the bending nozzle is 0.012 m³. Calculate the verticalcomponent of the anchoring forcing required to hold the nozzle in place and determine its direction. G=9.81 m/s². The density of water is 1000 kg/m³.NozzleArea-0.01m²P-35 kPaArea -0.025Figure 5: Q535 degreeChatGPT solution:This is a challenging problem that requires some knowledge of fluid mechanics and calculus. I will try tohelp you by explaining the steps and providing some hints.First, we need to identify the extensive property B and the specific property b for this problem. Since weare asked to calculate the vertical component of the anchoring force, we can choose B as the verticallinear momentum of the water in the nozzle and b as the vertical component of the water velocity. Notethat b is not constant and depends on the position and direction of the nozzle.Second, we need to apply the Reynolds transport theorem (RTT) to relate the rate of change of B for thesystem (the water in the nozzle) to the rate of change of B for the control volume (the pipe and nozzle)and the net flux of B across the control surface (the flange and nozzle outlet). The general form of RTT is[dB dt)system d dt///CVbp. dcSbpt-V. n). dAwhere p is the density, -V is the velocity vector, n is the outward-pointing unit normal vector, d VanddA are volume and surface elements, respectively.Third, we need to simplify the RTT equation by making some assumptions and using same given data. Forexample, we can assume that:The density p is constant ond omfarmThe flow is steady, which meam thin Oko.The velocity at the flange is hailprital and couelta 0/A11 wher as the discharge rate and A1 is theon area of the ange The velocity at the nozzle outlet is inclined at 35 degrees with respect to the horizontal direction andequal to Q/A2, where A2 is the outlet area.The anchoring force Facts vertically upward on the nozzle.Using these assumptions and data, we can write:[dB dt]system=0dat/fCvbp. d VFJJCSbpl V. n). dAfflangebp(-V. n). dA+/outletbp-V. n). dAwhere b = Vsind at both flange and outlet, 0-0 at flange and 9 = 35 degrees at outlet.Fourth, we need to evaluate the integrals over the control surface by using geometry and trigonometry.For example, we can find that:dA A1 at flange and dA = A2cos35 degrees at outletni at flange and 'n=cos35 degrees + sin35 degrees at outlet.-V. n-Q/A1 at flange and -V=Q/A2 at outletTherefore,fflangebp-V. n). dA= -pQ2/A1Joutletbpl-V. n) dA-pQ2sin35 degrees/A2Fifth, we need to substitute these values into the RTT equation and solve for F. We get-F=pQ2/A1 pQ2sin35 degrees/A2F=pQ2(1/A1-sin35 degrees/A2)Finally, we need to plug in the numerical values given in the problem statement and calculate F. We getF (1000 kg/m3)(0.1 m3/s/2/1/0.025 m2-sin35 degrees/0.01 m2)F-286 NThe direction of F is upward since it is positivethope this helps you understand how to use RTT to solve this problem, you have qufeedback please let me know

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