Q4) A force of magnitude F = 62 × 10° N is applied perpendicularly to the steel rod of radius 9.5 mm and length 70 cm. What is the increase in the length AL of the rod ( Young's modulus of steel is 2 x 1011 N/m² ). %3D A)0.77 mm B) 0.92 mm C) 0.67 mm D)0.47 mm F

Suppose a piano tuner stretches a steel piano wire 5.5 mm. The wire was originally 0.825 mm in diameter, 1.27 m long, and has a Young's modulus of 2.10 × 1011 N/m2. l0 = 1.27 ml = 5.5 mmd = 0.825 mm Calculate the force a piano tuner applies to stretch the steel piano wire in Newtons. F =

A lighting fixture can be hung from wires of identical size and shape made of aluminum, brass, or copper. The values of Young's modulus for these metals are 0.70 × 10^11 Pa (aluminum), 0.91 × 10^11 (brass), and 1.1 × 10^11 (copper). Which wire would stretch the greatest distance? A. Aluminum B. Copper C. Brass D.They will all stretch the same distance.

Calculate the force a piano tuner applies to stretch a steel piano wire 7.50 mm, if the wire is originally 0.850 mm in diameter and 1.35 m long. Young's modulus for steel is 210 x 109 N/m2. N