Q3/A- Estimate the result when you execute the following code by using Qbasic programming For m take the following values 100,90,80,70,60,50,40,30,20,10,30: Input "enter student mark"; m If m 100 Then Print "ful mark" Elself m >= 90 Then Print "accelent" Elself m> 80 Then Print "very good" Elself m> 70 Then Print "accepted" Print "fail" Else End If

Pythom:  Least Common Multiple, Greatest Common Factor (Grade Factor 1) This assignment assess problem solving ability and the use of the modulo operator, functions, lists and nested loops.   The Modulo (%) operator returns a remainder of the two numbers divided.  e.g. 9 % 2 will yield a 1 because 9/2 = 4 and the remainder is 1.   Write one program that will compute both the Least Common Multiple, and the Greatest Common Factor of two random numbers between 2 and 30. The program will display all factors and multiples of the two numbers.   When displaying the multiples of the numbers, only display up to the first input times the second input.   Use functions to compute the answers.   Loop the program so that the user try again.  create the loop so that hitting enter will continue.   The example is below: Integer1: 12Integer2: 3 The Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, The Multiples of 12 are 12, 24, 36, The lowest common Multiples is 12 The Factors of 3 are…

PLEASE SOLVE BOTH 2.) and 3.) 2.) What will be displayed when the following code is executed?int number = 6;while (number > 0) {number -= 3;System.out.print(number + " ");}a. 6 3 0b. 6 3c. 3 0d. 3 0 -3e. 0 -33.) Which of the following loops correctly computes 1/2 + 2/3 + 3/4 + ... + 99/100?A:double sum = 0;for (int i = 1; i <= 99; i++) {sum = i / (i + 1);}System.out.println("Sum is " + sum);B:double sum = 0;for (int i = 1; i < 99; i++) {sum += i / (i + 1);}               System.out.println("Sum is " + sum);C:double sum = 0;for (int i = 1; i <= 99; i++) {sum += 1.0 * i / (i + 1);}System.out.println("Sum is " + sum);D:double sum = 0;for (int i = 1; i <= 99; i++) {sum += i / (i + 1.0);}System.out.println("Sum is " + sum);E:double sum = 0;for (int i = 1; i < 99; i++) {sum += i / (i + 1.0);}System.out.println("Sum is " + sum);

Computer Science