Q3. Two protons in an atomic nucleus are typically sepa- rated by a distance of 2.3*10^-15 m. The electric repulsive force between the protons is huge, but the attractive nuclear force is even stronger and keeps the nucleus from bursting apart. What is the magnitude of the electric force between two protons separated by 2.3*10^-15 m (if you know that the charge of proton = 1.6*10-19)?

Red blood cells can often be charged. Consider two red blood cells with the following charges: -17.6 pc and +49.8 pC. The red blood cells are 3.31 cm apart. (1 pC = 1 × 10-12 C.) ..(a)..What.is.the magnitude of the force on each red blood cell? Enter a number. alculate the force of a charged particle on another charged particle? N Are the red blood cells attracted or repulsed by each other? attracted repulsed (b) The red blood cells come into contact with each other and then are separated by 3.31 cm. What magnitude of force does each of the red blood cells now experience? What is the net charge of the system? Assuming the cells are identical, how much charge will each have after contact? N Are the red blood cells attracted or repulsed by each other? attracted repulsed

Newer automobiles have filters that remove fine particles from exhaust gases. This is done by charging the particles and separating them with a strong electric field. Consider a positively charged particle +4.7 µC that enters an electric field with strength 2 x 105 N/C. The particle is traveling at 17 m/s and has a mass of 10-9 g. Tw What is the acceleration of the particle? (Enter the magnitude only.) m/s² What is the direction of the acceleration of the particle relative to the electric field? O It is in the same direction as the electric field. O It is 90° to the left of the electric field. It is 90° to the right of the electric field. It is in the opposite direction of the electric field.

A.) Which of the following statements are true? Choose all that are. The charge on particle A is 6 µC. The charge on particle B is 346 µC. The two particles are 58 cm apart. FE,A on B = FE,B on A- Electrostatically, electrons are repelled by neutrons. Quadrupling the distance between two charges increases the electric force between them by a factor of 16. For two charges with opposite polarities, FE > 0. In Coulomb's Law, k is the spring constant.