Q3). The following data were recorded in a field. Draw contour lines of 152m, and 154mby interpolation method with scale 1:250. All dimension and readings are in meter.stationBM1234567S910111213141516BMBS2.450IS0 6401.0501 1402.0003.9502.9002.4500.00001402.3003.3404.8003.3402.8900.6900.200FS2.450RemarkR.L. = 150m286591011121010-16151413

Answered: Image /qna-images/answer/6d480898-cbe1-44ab-aaa2-bae36124cb62.jpg

Q3). The following data were recorded in a field. Draw contour lines of 152m, and 154 by interpolation method with scale 1:250. All dimension and readings are in meter. station BS BM 2.450 IS FS Remark R.L. = 150m 16

Q3). The following data were recorded in a field. Draw contour lines of 152m, and 154 by interpolation method with scale 1:250. All dimension and readings are in meter. station BS BM 2.450 IS FS Remark R.L. = 150m 16

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Geometric space, i need solutions in 15 minutes please. MCQ/ To establish a new benchmark on point B using a levelling instrument. The work had been done between B.M1 and B.M2 to the required point B, and the surveys were recorded as in the tables below. Calculate the best. Value of elevation for point B. A-39.97m B-40.95m C-45.98m D-44.37m E-46.97m F-41.97m G-43.67m
N Rod ++ 50 1+50 1+75 2.6 Complete the set of differential leveling notes in Table 2-5, and perform the arithmetic 2.5 Prepare a set of profile leveling notes for the survey in Figure 2-34. In addition to comput- ing all elevations, show the arithmetic check and the resulting error in closure. check. 5.11 4.66 3.98 1.20 1.80 TP 2 4.42 4.30 2.01 Known Elevation is 402.78 4.72 TP 1 BM 61 Elevation = %3D 396.74 FIGURE 2-34 5-35 ()
Following are the notes for a line of stadia levels. The elevation of BM-A is 184.29m. The stadia interval factor is 100.00 and C = 0.381m. Rod readings are taken at height of instrument. Determine the elevations of remaining points and tabulate values accordingly. STA BACKSIGHT a S (m) BM-A 1.40+y -3°30' TP-1 0.97+y -2°33' TP-2 1.11+y 0°45' TP-3 0.79+y 2⁰00' B-M₁-B VD S (m) (m) FORESIGHT a 1.07 0.93 1.46 1.04 2⁰18' -3°56' -0°26' 8015' VD (m) DE (m) ELEV (m)
Calculate the interior angles from the following observations: Line PQ QR RS ST TP Bearing S 37° 30′ E S 43° 15' W N 73° 00′ W N 12° 45' E N 60° 00' E
Q.3. A levelling table is given below. a) Calculate the elevations of every station given in the table and show the arithmetic check. If there is an error, please distribute it to the elevations. E = 40* K b) Đraw an illustrative figure for the levelling survey given in the table. Distance Is FS Station BS H.I. Elevation (m) (m) BM A 0.916 1486.813 90 1 1.020 80 1.860 90 3 0.173 1.376 60 4 0.112 1.769 90 5 1.008 3.511 130 1.360 90 7 0.740 110 8 0.688 0.707 70 ВМ В 1.176 1481.201 2.
Situation E. A 100m tape is used to measure a distance between A and B which was recorded as 350.65m. It was found that the tape is 0.02m too short. 11. What is the correct measured distance AB? 12. If the same tape is used to layout a distance BC = 450m, what is the correct layout distance BC?
As per plan, the distance between two telephone poles is 356.35 meters. If the location of one is known in the field and the second is to be laid with a 100 m tape known to be 0.02 meter too long, along an average ground slope of 1%. Determine the actual length to be laid along the ground surface. Given: Nominal Tape Length L1 Required Distance to be Laid out Di correction due incorrect tape length Ci Ground slope S Solution correction per tape length (correction 100-m length) incorrect tape length Ci slope correction (approximate method) CSL cumulative correction per tape length (all sources of tape corrections) C total correction (correction for Di) tot C Tape too long (+) or too short (-)? write the sign only Is the total correction to be added or to be subtracted? Correct Distance to be laid out DC
20. Determine the area of the given traverse using DPD and DMD Method. LINE BEARING DISTANCE S 36°46'W N 57°11'W AB 44.84 BC CD 136.56 N1°45'E 12.03 N 72°10'E S 48°13'E DE 64.80 EA 106.72
For the sketch ATTACHED, determine the horizontal distance AB and the elevation of Point B Starting Elevation at A is 50.00’ S (slope dist.) = 822.48 feet, Z (zenith angle) = 88º, hi = 5.15’, r = 5.00’
None
D= Distance V= Vertical Dist S= Sight Distance Topic: Tacheometric Surveying Pls answer in COMPLETE solution. DIAGRAM/ILLUSTRATION of the solution is a must, for better understanding. 3 dec places all answers.