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- #include <stdio.h>#include <stdlib.h>int LineFunc(void);int main(){int a, b;printf("Enter a :");scanf("%d", &a);printf("Enter b :");scanf("%d", &b);LineFunc();printf("\n\n");system("pause"); }int LineFunc(void){int i,j;int a=1, b = 0, y; for (i = -10; i < 11; i++){for (j = 10; j > -11; j--){y = a * i + b;if (i == 0 ){printf("-");}else if (j == 0){printf("|");}else if (i == 0 && j == 0){printf("+");}else if (y == j){printf("*");}elseprintf(" ");}printf("\n");} } Could you please write the code that gives different results for each value in the chart?Q1:What is the output of the following codes? int x=3; int main(){ int x=12; { int x=10; coutb) { case 0: cout<#include using namespace std; int main() { int stop; int result; int n; } cin >> stop; result = 0; Type the program's output for (n = 0; n stop) { cout << "n=" << n; cout << endl; break; } } cout << result << endl; return 0; Input 7 OutputProgram: #include <stdio.h>#include <string.h>int main() { char s1[100],s2[100]; printf("Enter string1: "); gets(s1); printf("Enter string2: "); gets(s2); int i=strlen(s1); int j=strlen(s2); int count=0; while(count<=j){ s1[i]=s2[count]; count++; i++; } printf("After concatenation = %s",s1); return 0;} Q: Implement the above algorithms using functions in C++void fun(int i) { do { if (i % 2 != 0) cout =1); cout << endl; } int main() { int i = 1; while (i <= 8) { fun(i); it; } cout <#include<bits/stdc++.h>using namespace std;bool isPalindrome(string &s){ int start=0; int end=s.length()-1; while(start<=end) { if(s[start]!=s[end]) { return false; } start++; end--; } return true;}int main(){ string s; cout<<"ENTER STRING:"; getline(cin,s); int n=s.length(); bool flag=true; for(int i=1;i<n;i++) { string lowerHalf=s.substr(0,i); string upperHalf=s.substr(i,n-i); if(isPalindrome(lowerHalf) && isPalindrome(upperHalf)) { flag=false; cout<<"String A is:"<<lowerHalf<<"\n"; cout<<"String B is:"<<upperHalf<<"\n"; break; } } if(flag) { cout<<"NO\n"; } return 0;} change to stdio.h string.hInstructions: Kindly provide comments that explains the program code below. (NOTE: this is a C program language) #include <stdio.h> int fact_recur(int n){if(n==0) return(1);return(n*fact_recur(n-1));} int fact_for(int n){ int fact=1; for(int i=1;i<=n;i++){ fact=fact*i; return fact; } }int main(void) { int number; printf("input number is: "); scanf("%d",&number); printf("factorial using for loop: %d",fact_recur(number)); printf("\nfactorial using recursion: %d",fact_recur(number)); return 0;}Zybooks C++ 1.7 LAB: Introduction to data structures labs Step 1: Producing correct output Three commented-out lines of code exist in main(). Uncomment the lines and click the "Run program" button. Verify that the program's output is: 2 + 2 = 4 Unknown function: PrintPlus2 Secret string: "abc" Submit your code for grading. Your submission will pass the "Compare output" test only, achieving 1 of the possible 10 points. Step 2: Inspecting the LabPrinter class Inspect the LabPrinter class implemented in the LabPrinter.h file. Access LabPrinter.h by clicking on the orange arrow next to main.cpp at the top of the coding window. Member functions Print2Plus2() and PrintSecret() print strings using std::cout. Step 3: Implementing CallFunctionNamed() Remove the three uncommented lines from main(). Then implement the CallFunctionNamed() function in main.cpp to handle three cases: If functionName is "Print2Plus2", call printer's Print2Plus2() member function. If functionName is "PrintSecret",…Q1: 1. What is the output of this C code? void main(){ int a = 0, i = 0, b; for (i=0;i< 5; i++){ a++;continue; } cout<<"i="<plz make this code from this to enter number from 1-8 to let the user play and put all the notes, basically make this code 8 queen puzzle game to make the user play. #include <stdio.h>#include <stdlib.h> int count = 0;void solve(int n, int col, int *hist){ if (col == n) { printf("\nNo. %d\n-----\n", ++count); for (int i = 0; i < n; i++, putchar('\n')) for (int j = 0; j < n; j++) putchar(j == hist[i] ? 'Q' : ((i + j) & 1) ? ' ' : '.'); return; } # define attack(i, j) (hist[j] == i || abs(hist[j] - i) == col - j) for (int i = 0, j = 0; i < n; i++) { for (j = 0; j < col && !attack(i, j); j++); if (j < col) continue; hist[col] = i; solve(n, col + 1, hist); }} int main(int n, char **argv){ if (n <= 1 || (n = atoi(argv[1])) <= 0) n = 8; int hist[n]; solve(n, 0, hist);}ê #include using namespace std; int main() { int count = 5; int num = 2; while (count r && num ){ cout << count << " " << num << endl; count -=1; if (count % 2 == 0) num -=1; } return 0; Output: 52 4 1 3 1 20 10#include #include using namespace std; int main() { double pi = 0; long i; long n; cin >> n; cout << "Enter the value of n: "; cout << endl; if (i % 2 == 0) else pi = pi + pi = pi T - (1/(2* i + 1)); (1/(2*1 + 1)); for (i = 0; i < n; i++) } { pi = 0; pi 4 pi; } cout << endl << "pi = " << pi << endl; return 0;Recommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. 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