Q3: Design 5/16-in SMAW fillet welds for the plate shown in figure below if A36 steel and E70 Electrode are used, Dead Load=40 kips, Live Load=60 kips." PL x 12 PLX8

130% v - + 7 Annotate T| Edit Trial expired Unlock Full Version ENGR 263 A A A EXERCISES Eleven sets of illustrations and the corresponding free-body diagrams of building-related beams were provided in Chapter 4 as Exercises 4. I through 4.11. These free-body diagrams constitute exercises that will be used here and again in Chapter 12. Follow these instructions carefully to save time later: (a) On each sheet of engineering paper reserved for analysis, calculate the vertical shear specific to that member at appropriate intervals across the length of the free-body diagram. Be sure to solve for locations where shear passes through zero. (b) On cach sheet of engineering paper containing the tree-body diagram, neatly draw the related shear diagram directly below the associated free-body diagram. The shear diagram should be located in the middle one-third of the page. Reserve the bottom one-third of the sheet for the bending moment diagram introduced in Chap- ter 12. Be sure to show…

See the image. Two steel plates are welded together. The thickness of the bottom plate is 10mm and the thickness of the top plate is 8mm. What is the maximum and minimum sizes of the weld.

All measurements shown in mm. The connected plates are 10mm. Apply NSCP Specs for welded connections. Fy =420MPa, Fu = 580MPa. L2is the length of the transverse weld. Note: L1 = 500mm, L3 = 500 & width = 300mm. 1. Determine the maximum weld thickness that can be used.2. Determine the effective weld length of each weld if the actual welds used in the connection is 4mm. L2 =300mm.3. If the plates used are 10 mm, determine the tension yielding and rupture capacity. Consider θ = 0°, L2 = 0 and LRFD NSCP 2015.4. If the welds used are 8 mm, determine the weld capacity. Consider θ = 0°, L2 = 300mm. Weld strength, Fw = 485MPa. LRFD.5. If the welds used are 8 mm, determine the weld capacity. Consider θ = 30°, L2 = 0mm. LRFD.