Q3: A cylindrical specimen of steel having an original diameter of (12.8mm) is tensile tested to fracture and found to have engineering fracture strength of (450MP ). If its cross-sectional diameter at fracture is (10.7mm), determine: (1) the ductility in terms of percent reduction in area and (2) the true stress at fracture.

A cylindrical metal specimen having an original diameter of 10.63 mm and gauge length of 50.1 mm is pulled in tension until fracture occurs. The diameter at the point of fracture is 7.60 mm, and the fractured gauge length is 74.5 mm. Calculate the ductility in terms of (a) percent reduction in area (percent RA), and (b) percent elongation (percent EL). (a) i percent RA (b) i percent EL

Please answer d,e,f

A steel specimen is tested in tension. The specimen is 1" wide by 0.5" thick in the test region. By monitoring the stresses from the testing machine, it was found that the specimen yielded at a stress of 72 ksi and fractured at 96 ksi. (a). Determine the tensile loads at yield and at fracture

A component made of Aluminium 6061-T651 has an edge crack with length equal to 15 mm, as shown The yield stress of the material is oy = 280 MPa and its fracture toughness (Kic) ranges from 40 MN/m3/2 to 60 MN/m³/2 Consider now the same edge crack in a semi-infinite plate. Determine the critical stress to avoid fracture. P I I I I ← 15 mm P↓ 100 mm 30 mm

Sample: Malleable Steel (AISI 4145) Original Diameter: 6.14mm Final Diameter: 3.54mm Gauge Length: 55 mm Final Length: 68.12 mm

(a) the modulus of elasticity in GPa for the Aluminum  B)  the proportional limit in MPa for the Aluminum   C)  the ultimate strength in MPa for the Aluminum  D) Ductility of material based on percent elongation

Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failure

I need the answer as soon as possible

2. The Goodman diagram relates oa and om for fatigue failure after a specific number of cycles Nf, where da is the cyclic stress amplitude, and om the mean stress. For a steel specimen it is found that oa oa (0). [1- (om/OTS)] where Ors is the metal's tensile stress (375MPa), and oa (0)~0.450TS is the 107 cycle fatigue limit at zero mean stress. Assuming the specimen is cycled repeatedly between 0 stress and a peak stress, what is the maximum peak stress if failure in < 107 cycles is to be avoided? Ans: 233 MPa