Q2/ The rigid bar ABCD is supported by a pin at B and restrained by identical steel bars at C and D, each of area 250 mm². If the temperature is increased by 80°C, determine the force P that will cause the bar at C to be stress-free. Use E = 200 GPa and a=12.8*106/C 3 m 0.8 m -0.6 m CeD
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- An elevated jogging track is supported at intervals by a wood beam AB (L = 7.5 ft) that is pinned at A and supported by steel rod BC and a steel washer at B. Both the rod (dBC= 3/16 in.) and the washer (dB= 1.0 in.) were designed using a rod tension force of TBC=415 lb. The rod was sized using a factor of safely of 3 against reaching the ultimate stress tru— 60 ksi. An allowable bearing stress sba= 565 psi was used to size the washer at B. A small platform HF is suspended below a section of the elevated track to support some mechanical and electrical equipment. The equipment load is uniform load q = 50 lb/ft and concentrated load WE= 175 lb at mid-span of beam HF. The plan is to drill a hole through beam ABaX £land install the same rod (dBC) and washer) dB) at both D and F to support beam HF. (a) Use s and to check the proposed design for rod DF and washer d,: are they acceptable? (b) Re-check the normal tensile stress in rod BC and bearing stress at 8 if either is inadequate under the additional load from platform HF. Re-design them to meet the original design criteria.Q2/ The rigid bar ABCD is supported by a pin at B and restrained by identical steel bars at C and D, each of area 250 mm2. If the temperature is increased by 80°C, determine the force P that will cause the bar at C to be stress-free. Use E = 200 GPa and a=12.8*10PC 3 m 0.8 m l0.6m CaThe horizontal steel rod, 2.5 m long and 1200 mm2 in crosssectional area, is secured between two walls as. If the rod is stress-free at 20_C, compute the stress when the temperature has dropped to _20_C. Assume that (1) the walls do not move and (2) the walls move together a distance Δ = 0.5 mm. Use α = 11.7x10-6 oC and E = 200 GPa.
- 3. The rigid bar ABC and EFG are supported by pins at A and G. The vertical rods are made of steel (rod DC and rod BE). Determine the vertical displacement at C if the change in temperature is 50°C. Use a = 0.0000117/°C and E = 200 GPa. Neglect the weight of the members. A=125 sq. mm L= 2 m A 2 m B 2 m A=135 sq. mm L = 3 m E G 2 m F 3 m 50 kNFill in the blanks: The steel rod is stress-free before the axial loads P₁ =169 kN and P2 = 88 kN are applied to the rod. Assuming that the walls are rigid, calculate the axial force in each segment after the loads are applied. Use E-200 GPa. A = 2000 mm² A = 900 mm² A = 1200 mm² P P₁ B с D -250 +₁3 500 mm mm- 350 mm- ANSWER: KN, PBC = PCD = KN KN, PAB = (express it in whole number) ATwo vertical steel rods support the rigid bar as shown. Initially, the rods are stress-free. Given the data below, determine the stress of rods A and B after the 20 kN load is applied. Neglect the weight of the bar and use E = 200 GPa for steel. L= 3 m D = 3.5 mm A. Stress of rod A (MPa) B B. Stress of rod B (MPa) C. At what temperature AT change would the stresses for both rods be equal? Use a = 11.7 L= 4 m x 10-6 mm/mmC° (C°) D = 5 mm 4m 2m 2m 20 kN
- A piston-cylinder has a force F₁ applied to it. The circumferential stress in the cylinder cannot exceed Omax = 6 MPa. Hint: 1. Pressure = F Area P = F₁ F₁- OG Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value T'inner 44 mm t 1.25 mm r1 a. Determine the max pressure that the piston-cylinder can withstand, P. b. Determine the magnitude of max force that can be exerted on the piston to not exceed omax, F1. kPa NQ1/ The aluminum and bronze cylinders are centered and secured between two rigid end-plates by tightening the two steel bolts. There is no axial load in the assembly at a temperature of 50°F. Find the stress in the steel bolts when the temperature is increased to 200°F. Use the following data: Aluminum cylinder Bronze cylinder Each steel bolt A (in.²) 2.00 3.00 0.75 a (/°F) 12.8 x 10-6 10.5 x 10-6 6.5 x 10-6 E (psi) 10 x 106 12 × 106 29 x 106 1.0 in.- -3 in 4 in.-1.0 in. Aluminum Bronze OA bar of square cross-section is subjected to point loads of P1, P2, P3, and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 130 kN, P2 = 230 kN & P4 = 180 kN. Also, determine the stresses in each section & the net change in the length of steel bar, where the respective side of a square and lengths are d1=55mm, L1=31 cm, d2 = 40mm, L2=38 cm, d3=55 mm & L3 =30 cm. Take E = 185 GPa. The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Stress in section 2 in N/mm2 is The Stress in section 3 in N/mm2 is and The total change in length in x10-3 mm is
- Let's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: O F=15708 N O F= 5236 N O F= 6283 N O F=4189 N O F= 10472 N O F= 13090N Clear my choice Finish attempt. IOUS ACTIVITY 360 Test - Spring 2020-2021 Jump to. 11:21 PM 4) G ENG 4/15/2021 LEGO ort sc delete end home backspace num lock 7V home enter 4E K pause MThe rigid bar ABCD of negligible weight is initially horizontal, and the steel rods attached at A and C are stress free. 26 kips load is then applied and the temperature of the steel rods is changed by AT. Find AT for which the stresses in two steel rods will be equal. Use a = 6.5 x 10"/°F and E = 29 x 10°psi for steel. A = 0.6 sq. in 3 ft 5 ft 5 ft D A 3 ft B 4 ft A = 0.8 sq. in V 26 kipsThe rigid bar AB of negligible weight is supported by a pin at 0. When the two steel rods are attached to the ends of the bar, there is a gap D= 4 mm between the lower end of the left rod and its pin support at C. Compute the stress in the left rod after its lower end is attached to the support. The cross-sectional areas are 300 mm2 for rod AC and 250 mm2 for rod BD. Use E= 200 GPa for steel. lo/0 0.75 m 1.5m 2 m ANSWER: MPa