Q2 Let f(x) = 2x³ – 0.0064x² – 1.5x + 0.454 (a) Indicate that f (x) = 0 has a root in the interval [-3, 0] with |bo – a] = 1. (b) Examine which method is less iteration (i) to find the root in Q2 (a) by using Secant method. Stop iteration if |f(x;)| < 0.0005 or i >7 .
Q2 Let f(x) = 2x³ – 0.0064x² – 1.5x + 0.454 (a) Indicate that f (x) = 0 has a root in the interval [-3, 0] with |bo – a] = 1. (b) Examine which method is less iteration (i) to find the root in Q2 (a) by using Secant method. Stop iteration if |f(x;)| < 0.0005 or i >7 .
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Q2 Let f(x) = 2x3 – 0.0064x² – 1.5x + 0.454
(a) Indicate that f(x) = 0 has a root in the interval [-3, 0] with |b, – a,| = 1.
(b) Examine which method is less iteration (i) to find the root in Q2 (a) by using Secant
method. Stop iteration if |f(x;)|< 0.0005 or i > 7 .](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ded123e-d4a9-414c-91df-9810e4e8e92b%2F19a8632f-543b-41f9-bc84-ed66b55f0fa2%2Fuemam5e_processed.png&w=3840&q=75)
Transcribed Image Text:Q2 Let f(x) = 2x3 – 0.0064x² – 1.5x + 0.454
(a) Indicate that f(x) = 0 has a root in the interval [-3, 0] with |b, – a,| = 1.
(b) Examine which method is less iteration (i) to find the root in Q2 (a) by using Secant
method. Stop iteration if |f(x;)|< 0.0005 or i > 7 .
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