Q2 :Given that the equation x2 – kx + 8 = 0 where k ER has one of the solutions is x = 2 - j2. find the second solution and the value of k Q3: If a – 2 + jb = 6 + j2.where a and b are known to be real numbers. Find a and b

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Q2 :Given that the equation x2 – kx + 8 = 0 where k ER has one of the solutions is
x = 2 – j2. find the second solution and the value of k
Q3: If a – 2 + jb = 6 + j2. where a and b are known to be real numbers. Find a and b
Q4 : solve 1) e? = 1 + jv3
2) z3 – 1 = jv3
3) e2z-1 =
05: prove
Transcribed Image Text:Q2 :Given that the equation x2 – kx + 8 = 0 where k ER has one of the solutions is x = 2 – j2. find the second solution and the value of k Q3: If a – 2 + jb = 6 + j2. where a and b are known to be real numbers. Find a and b Q4 : solve 1) e? = 1 + jv3 2) z3 – 1 = jv3 3) e2z-1 = 05: prove
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