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Q2: Find Req. for the circuit shown in the figure below? 1.5Ω Solution: ww Rea 1.52 1.50 ww ww ww

Q2: Find Req. for the circuit shown in the figure below? 1.5Ω Solution: ww Rea 1.52 1.50 ww ww ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Q2: Find Req. for the circuit shown in the figure below?** **Solution:** The diagram shows a complex electrical circuit composed of several resistors. The resistors are arranged in a combination of series and parallel configurations. - There is a 3Ω resistor connected in series at the top. - Parallel to this 3Ω resistor, a combination of resistors is present: a 2Ω resistor and another branch that has two 2Ω resistors in parallel. - The parallel branch connects to a 1.5Ω resistor on both sides, which further connects to a 1.5Ω resistor in series at the bottom. To find \( R_{eq} \), or the equivalent resistance: 1. Calculate the equivalent resistance for the two 2Ω resistors in parallel: \[ R_{parallel} = \frac{1}{\frac{1}{2} + \frac{1}{2}} = 1Ω \] 2. This 1Ω resistance is in series with another 2Ω resistor (same branch), giving: \[ R_{series} = 1Ω + 2Ω = 3Ω \] 3. This resulting 3Ω is in parallel with the top 3Ω resistor: \[ R_{combined} = \frac{1}{\frac{1}{3} + \frac{1}{3}} = 1.5Ω \] 4. Add the series resistances along the bottom: \[ R_{eq} = 1.5Ω + 1.5Ω = 3Ω \] The equivalent resistance of the circuit \( R_{eq} \) is 3Ω.
Transcribed Image Text:**Q2: Find Req. for the circuit shown in the figure below?** **Solution:** The diagram shows a complex electrical circuit composed of several resistors. The resistors are arranged in a combination of series and parallel configurations. - There is a 3Ω resistor connected in series at the top. - Parallel to this 3Ω resistor, a combination of resistors is present: a 2Ω resistor and another branch that has two 2Ω resistors in parallel. - The parallel branch connects to a 1.5Ω resistor on both sides, which further connects to a 1.5Ω resistor in series at the bottom. To find \( R_{eq} \), or the equivalent resistance: 1. Calculate the equivalent resistance for the two 2Ω resistors in parallel: \[ R_{parallel} = \frac{1}{\frac{1}{2} + \frac{1}{2}} = 1Ω \] 2. This 1Ω resistance is in series with another 2Ω resistor (same branch), giving: \[ R_{series} = 1Ω + 2Ω = 3Ω \] 3. This resulting 3Ω is in parallel with the top 3Ω resistor: \[ R_{combined} = \frac{1}{\frac{1}{3} + \frac{1}{3}} = 1.5Ω \] 4. Add the series resistances along the bottom: \[ R_{eq} = 1.5Ω + 1.5Ω = 3Ω \] The equivalent resistance of the circuit \( R_{eq} \) is 3Ω.
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