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- A conditioned space has a calculated heat loss at the design maximum heating day of 10,000 BTUs / Hr to maintain an interior temperature of 70 F. We will use a hydronic baseboard style convector to heat the space. The style we have chosen comes in standard lengths. At rated temperature and flow of hydronic heating fluid for each 1 foot of length the heater will add 750 BTUs /Hr to the room. What length of heater can just maintain the temperature on the worst day? For this example we are ignoring other sources of heat loss such as ventilation or drafts.Q3/ Calculate the cooling load for a ceiling is constructed from 152.4 mm lightweight concrete (I.W concrete) and without a suspended ceiling, dark colour (k-1) and no mechanical ventilation (f = 1). Area= 25 m². The building at 32° North latitude at time 14 on 21 of August, outdoor design temperature 35 °C, daily range DR-11.2 °C and indoor design temperature 25.5 °C.QL.Compute the total heat gain load from all the sources into the lunchroom ,if the lunchroom is located at the top floor of an air conditioned commercial building. The lunchroom has one exposed wall facing SE. -Wall facing SE, (20 * 15); 12 brick, the overall heat transmission value(U) is 0.3 Btu/hr.ft². F. -Roof; 6 concrete with 2" insulation, Uroof 0.4 Btu/hr.ft².F - Windows facing SE ;No.(3), (3 *3),single regular plate,double-hung metal windows,weather-stripped; unlocked ,shaded with white inside roller shade,half drawn. -Occupants: (10) persons; sedentary work. -Lightening :2 Watt /ft² of the floor area (40' *20) -Outside conditions: T= 100 F (db) & T70(wb), DR =25 F, Vwind -10 mph. -Inside conditions: T-70 F (db) & Q=40%. -Location: 40 N.L, Time = 11 A.M.
- 2. Calculate the heat loss for the structure described below. Use the indoor design setpoint of 70°F. ● . . . ● ● Hint: Utilize the Q=U*A*(ti-to) & Q = U'*P*(ti-to). Make sure to reference the following tables and examples to help assist you solve this problem; Table 5-5a, Table 5-8, Table 5-4a, Example 5-3, Eq. 5-23, and Fig 5-8. Given: i. Location: Des Moines, IA @ 99% winter OAT ii. Walls: Table 5.7, Construction 2 iii. Floor: Concrete slab with 2-ft, R-5.4, vertical edge insulation iv. Windows: Double-Insulating Glass; 1/4-in. air space; e = 0.6 on surface 2, 3x4-ft, double hung, reinforced vinyl frame; three on each side v. vi. Roof-Ceiling: Same as Example 5.3, height of 8-ft vii. House Plan: Single story, 36-ft x 64-ft Doors: Wood, 1-3/4-in. panel doors with metal storm doors, three each, 3x6.75-ft Qwindows = Qdoors= Qwalls = Qroof/ceiling= Qfloor = QTOTAL = Btu/(hroft²0F) Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat LossQ4/ A room on the second floor of a house with a balcony has a door. The door made of teak (wood) and it contains a large sheet of glass (outside winter type) in the middle and constitutes 80% of the area of the door. Door thickness is 40 mm and the temperature in the room 25. °C when the temperature is in the balcony 8 °C. Calculate the rate of heat loss from the room to the balcony through the door. The door dimensions 2m x 1m. Assume Inside and outside still air thermal resistance f= 8.29 W/m2 °C and f. 34.1 W/m2 °C respectivelyThe thermal conductivities of wood is kwood = 0.1W/(m°C)and air is kair = 0.0234W/(m°C). Part A If the temperature of the room is 20°C and outside is 10°C, find the rate of heat flow for a wall of wood with area = 10 m² and thickness of 5cm. O 60 W O 304 W O 34 W O 200 W O 100 W Submit Request Answer Part B The wall of wood with thickness of 5cm is now replaced with two layers of wood and a gap of air between the wood. Each layer of wood has a 2.5cm thickness and the gap is 1cm. The rate of heat flow will, decreases. increases. stay the same. Submit Request Answer Part C The temperature in the air gap will be, O 20°C, between 10°C and 20°C, O 10°C,
- 2b. List tools which can be used to for minutes ahead forecasting? Compare the geo-thermal technologies used at different 2c. temperaturesV:01 Expert Q&A Done Question 1: In your own words, write down the differences between thermodynamic and heat transfer. (3 Marks) Question 2: Estimate the heat loss per square metre of surface through a brick wall 0.5 m thick when the inner surface is at 400 K and the outside surface is at 300 K. The thermal conductivity of the brick may be taken as 0.7 W/mK. (2 Marks) Question 3: A furnace is constructed with 0.20 m of firebrick, 0.10 m of insulating brick, and 0.20 m of building brick. The inside temperature is 1200 K and the outside temperature is 330 K. If the thermal conductivities are as shown in the figure below, estimate the heat loss per unit area. (5 Marks) 1200 K 330 K Insulating brick X-0.10m k= 0.21 Ordinary brick X=0.20 m Fire brick X= 0.20 m k= 1.4 k= 0.7 (W/mK)Find the rate of heat loss per sq meter per hour and interface temperatures
- 36 -S 42 2. Metal castings can sometimes develop a gap between the casting and mold as the molten metal hardens. The result can be a substantially altered cooling process. Set up a simple heat-transfer model that would let you look at the effect of the gap on the cooling process. Assume the casting and mold are square in shape, with an air gap of thickness das shown in the figure. The mold sits in some ambient room temperature. State clearly all assumptions and develop a corresponding model of the heat transfer problem. Assuming that the casting is aluminum, the mold is diatomaceous earth and the gap is filled with air, see if you can arrive at and summarize some insight into the effect of the gap and its size on the heat transfer process.you are assigned by your food engineering professor to assist a food manufacturing company as part of your task. On your first day of report, the owner wants to know if their furnace is still in condition, in which the heat loss per square meter should be at least 1,000 W/m2. The details of the furnace are as follows. The furnace wall is 1m by 1m. It is made up of 3 layers, in which the inner wall is made up of fire brick, followed an insulating brick and finally, red brick for the outer layer. You checked the inside surface temperature and got a temperature of 870oC which is 830oC hotter than the outer surface. Other data are provided from the furnace manual and specs. Co-efficient of thermal conduciveness and thickness of the layers are as follows: 1.0 W/m-K, thickness: 22 cm 0.12 W/m-K, thickness: 7.5 cm 0.75 W/m-K, thickness: 11 cmI need right solution with clear calculations. A workplace is occupied by 100 people who are averaging 250 Watts/person. The space is measured as 30 meters x 20 meters x 15 meters (L x W x H). What is the internal heat gain of this space given off by a full staff? If you need to provide the workplace 10 air changes per hour, what type of infiltration inflow rate need to be (cubic meters/hour)?